I (I must find the equation of the sphere that is tangent to 2 planes.

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Homework Help Overview

The original poster is tasked with finding the equation of a sphere that is tangent to two given planes and passes through specific points A, B, C, and D. The planes are defined by their equations, and the problem involves understanding the geometric relationships between the sphere and the planes.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the nature of the two planes and their parallelism, suggesting that the distance between them is relevant for determining the sphere's diameter. There are questions about the role of points A, B, C, and D in defining the sphere, with some participants proposing methods to find the center of the sphere using perpendicular bisectors and distances.

Discussion Status

Participants are exploring various interpretations of the problem, with some suggesting methods to calculate distances and find the sphere's center. There is acknowledgment of multiple spheres that could satisfy the conditions, and guidance has been offered regarding the use of normals and distances in the context of the planes.

Contextual Notes

There is some confusion regarding which sphere is being sought, as multiple spheres can be tangent to the same two planes. The original poster's professor provided hints that reference point D, which adds complexity to the problem. The discussion reflects uncertainty about the specific requirements of the problem.

afcwestwarrior
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Homework Statement


My professor gave us 4 points A(2,3,-5) B(-2,5,1) C(9,0,4) D(3,-5,8)
So I must find an equation of the sphere that is tangent to 2 planes. These 2 planes are
18x + 39y - z= 158
18 x + 39y -z = -149

Homework Equations



equation of sphere C(h,k,l) (x-h)^2 + (y-k)^2 + (z-l)^2 = r^2

The Attempt at a Solution


Ok How do I find it's center and it's radius. I'm not sure as to what I do. I've never seen this type of problem written like this before. So I need help. My professor gave us a hint. He said something about the D point. Will the distance formula give me the center. From A to D.

The Vectors of these planers are <18,39, -1>
 
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Notice that the planes are parallel (i.e. don't intersect) so always maintain the same distance. Find how far apart the planes are when traveling along the perpendicular to the two planes you're given, that will give you the diameter. Then the center is just halfway between the planes when traveling along a perpendicular (notice there are lots of possibilities for this)
 


I'm going to guess that A, B, C and D are supposed to be points on the sphere? Where did you get the two planes from? Notice that for any two points on the sphere, like A and B, the center of the sphere must lie on the plane that perpendicularly bisects the segment AB. You can actually find three planes to intersect to find the center of the sphere. Say AB, BC and BD.
 


I got the 2 planes from the 1st and 2nd question.
Find the equation of the plane that contains A,B, and C.

Find the equation of the plane parallel to the plane you found in part a and also contains the point D.
 


In order for me to find the distance between these 2 planes do I use this formula.
D= (a x1 + b y1 + c z1 + d) / square root of (a^2 + b^2 + c^2 )

Their's an absolute value for the numerator.
I got 307 by adding 158 with 149.
A= 18
B=39
C= -5


D= 307 / square root of (18^2 + 39^2 + (-5)^2 ) = 7.09

Then D/2 so 7.09/2 = 3.545
 


afcwestwarrior said:
I got the 2 planes from the 1st and 2nd question.
Find the equation of the plane that contains A,B, and C.

Find the equation of the plane parallel to the plane you found in part a and also contains the point D.

Fine, but which sphere do you want? Given two planes there are MANY spheres tangent to both of them.
 


So if C is 3.545 how do I find it's points
 


Their are many spheres. I perpindicular to point D is the sphere that I want.
 


So I can choose any of those 4 points.
 
  • #10


afcwestwarrior said:
So I can choose any of those 4 points.

That's still not very clear. I'll repeat. Do you want the sphere that goes through A, B, C and D?
 
  • #11


So the center must be (18, 39, and -1). And the point I'll choose is D (3,-5,8)

Then I'll use the Distance formula DC= square root of (3-18)^2 + (-5-39)^2 + (8+1)^2

=square root of 2242

then I square it and I get r= 2242

so the answer is

(x-18)^2 + (y-39)^2 + (z+1)^2 =2242

does that look correct
 
  • #12


I wanted to choose the sphere that goes through the point D
 
  • #13


afcwestwarrior said:
So the center must be (18, 39, and -1). And the point I'll choose is D (3,-5,8)

Then I'll use the Distance formula DC= square root of (3-18)^2 + (-5-39)^2 + (8+1)^2

=square root of 2242

then I square it and I get r= 2242

so the answer is

(x-18)^2 + (y-39)^2 + (z+1)^2 =2242

does that look correct

Hard to say, since I haven't figured out what problem you are actually trying to solve.
 
  • #14


I had to find the equation of the sphere tangent to the 2 planes
 
  • #15


afcwestwarrior said:
I had to find the equation of the sphere tangent to the 2 planes

Ah, ok. So tangent to the two planes and passing through D. I would use the unit normal to the planes and the dot product. Since you know the normal is n=(18,39,-1) the unit normal is u=n/|n|. Then d=(A-D).u is the signed distance between the two planes. And the center must be located one half that distance away in the direction u. So the center is D+u*d/2.
 
  • #16


You sure this will work. I will try this out. Thanks man.
 

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