I know this might be easy but i forgot how to solve

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Please help me..

integrate this

\int\frac{1}{U\sqrt{1-U^2}}dU
 
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..Try using integration by parts and see if you can solve

u=\frac{1}{U} find du/dx
\frac{dv}{dx}=\frac{1}{\sqrt{1-U^2}} so get v=

and

\int u\frac{dv}{dx}dx=uv-\int v\frac{du}{dx}dx
 
It can be done straightforwardly with a trig substitution, like u=sin(t).
 
Sorry but...

the original question wasintegration from \epsilonto\pi-\epsilon
\int\frac{1}{sinx}dx

I tried to integrate it straight but i don't know how calculate cosec and cot...
 
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Try the substitution u = tan(x/2).
 
:)thanks guys. I got it~
 
What is the term for the slope on an x-axis that runs parallel but never actually touches the x axis?
 
Get your own thread. But until you do 'horizontal asymptote with y value 0'.
 

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