Dec 1, 2007 #1 idiotblue Messages 4 Reaction score 0 Please help me.. integrate this \int\frac{1}{U\sqrt{1-U^2}}dU
Dec 1, 2007 #2 rock.freak667 Homework Helper Messages 6,221 Reaction score 31 ..Try using integration by parts and see if you can solve u=\frac{1}{U} find du/dx \frac{dv}{dx}=\frac{1}{\sqrt{1-U^2}} so get v= and \int u\frac{dv}{dx}dx=uv-\int v\frac{du}{dx}dx
..Try using integration by parts and see if you can solve u=\frac{1}{U} find du/dx \frac{dv}{dx}=\frac{1}{\sqrt{1-U^2}} so get v= and \int u\frac{dv}{dx}dx=uv-\int v\frac{du}{dx}dx
Dec 1, 2007 #3 Dick Science Advisor Homework Helper Messages 26,254 Reaction score 623 It can be done straightforwardly with a trig substitution, like u=sin(t).
Dec 1, 2007 #4 idiotblue Messages 4 Reaction score 0 Sorry but... the original question wasintegration from \epsilonto\pi-\epsilon \int\frac{1}{sinx}dx I tried to integrate it straight but i don't know how calculate cosec and cot... Last edited: Dec 1, 2007
Sorry but... the original question wasintegration from \epsilonto\pi-\epsilon \int\frac{1}{sinx}dx I tried to integrate it straight but i don't know how calculate cosec and cot...
Dec 2, 2007 #5 Avodyne Science Advisor Messages 1,393 Reaction score 94 Try the substitution u = tan(x/2).
Dec 13, 2007 #7 cummins Messages 2 Reaction score 0 What is the term for the slope on an x-axis that runs parallel but never actually touches the x axis?
What is the term for the slope on an x-axis that runs parallel but never actually touches the x axis?
Dec 13, 2007 #8 Dick Science Advisor Homework Helper Messages 26,254 Reaction score 623 Get your own thread. But until you do 'horizontal asymptote with y value 0'.