I need a little intuition my way regarding moments and direction of couples

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SUMMARY

The discussion centers on determining the tension T in a tape and the reaction forces at point C in a mechanical assembly involving a frictionless spool. The reactions at C are represented as C = and the moment M as M = <0, My, Mz>. The user expresses confusion regarding the direction of forces and couples, particularly how a vertical downforce of 6 lb affects rotation about shaft FG and the resultant couple in the z direction. Clarification is sought on the interplay between the welded connection and the forces acting on the assembly.

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  • Basic principles of tension in cables and ropes
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Homework Statement


The assembly shown is used to control the tension T in a tape that passes around a frictionless spool at E. Collar C is welded to rods ABC and CDE. It can rotate about shaft FG but its motion along the shaft is prevented by a washer S. For the loading shown, determine (a) the tension T in the tape, (b) the reaction at C.

Homework Equations


In the solution manual it says the reactions are as follows, C = <Cx,Cy,Cz> and M=<0,My,Mz>
Actually, C i kind of understand it, but not tally sure, and M i have no clue…

The Attempt at a Solution


I Just need help regarding the direction of the forces and couples.
My understanding is that because there's a welded connection, the weld will provide support from moving the rods, therefore the reaction at C goes in the x,y and z directions. However, if there's a vertical downforce at the end of the rod ( 6 lb) wouldn't that cause a rotation about FG and therefore cause a couple in the z direction only?
 

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Don't forget the force from the rope. It goes in a different direction.
 

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