Jane is riding her new bike at a constant velocity of 3 m/s when she goes past Tom. Tom notices that the road will come to an end with a 30m drop. Tom grabs his bike and attempt to catch up to Jane. Jane has a 20 sec head start. Tom is going to ride at a constant acceleraion of 1/2 m/s^2 for 20 sec then at a constant velocity until he rescues Jane or Jane rides to disaster. when Tom has been traveling for 8 sec Jane see that he is trying to catch up and accelereated at a rate of 5/12 m/s^2 for 12 sec then continuing at a constant velocity.
A) if the road is 375 m. long will Tom rescue her?
B) is jane flies over the edge, how many seconds before she hits the ground?
C) if Tom does catch up to Jane, how long after Tom starts will he catch up to Jane?
The Attempt at a Solution
i found Toms velocity using a=vt and got 10m/s
jane has been traveling at 3ms for 28 sec.
janes velocity after she starts to accelerate , using a=vt, is 5 m/s
Jane traveled 84 meters at a constant velocity of 3m/s and.
Tom went a total of 200 meters while accelerating.
Jane wen 60 more meters after she started to accelerate.
i dont really know what to do from here. how do i start?