I with chemical equilibrium problems

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To solve the chemical equilibrium problem involving the equation 3A + 2B ⇌ C + D with K = 1.00 x 10^-3, the equilibrium concentrations of A, C, and D are provided. The equilibrium constant expression relates the concentrations of the reactants and products: K = [C][D] / [A]^3[B]^2. Given the concentrations of A, C, and D, the next step is to rearrange the equation to solve for B. By substituting the known values into the equilibrium expression, B can be calculated step by step. Understanding this setup is crucial for accurately determining the unknown concentration in equilibrium problems.
allistair3421
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1. okay so the equation is:
3A+2B---->C+D
K=1.00x10(to the negative third power)
A=9.5-M C=0.0200-M D=0.0200 what is B ?



3. the answer is either 1.24: 0.0216: : 0.00180 : or 0.110
(i don't remember) so what i don't get is HOW DO I SET UP THE PROBLEM? :confused:

go step by step if you can and if you know some sites that would help post those too o_O
 
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If you have some chemical reaction:

aA + bB ----> cC + dD

At equilibrium, the concentration of A, B, C and D are related to the equilibrium constant, K:

<br /> K = \frac{[C]^c [D]^b}{[A]^a <b>^b}<br /> </b>

Where a, b, c and d are the stoichiometric coefficients.

How can you apply this to the given problem?
 
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