I need some help with an electricity problem

  • Thread starter Thread starter benji
  • Start date Start date
  • Tags Tags
    Electricity
AI Thread Summary
The discussion revolves around a physics problem involving a charged sphere and the forces acting on it. The user has attempted to calculate the angle and tension in the wire using free-body diagrams and trigonometric functions but has arrived at incorrect answers. Key suggestions include considering the effects of the electrical force as the sphere moves and applying Newton's second law to analyze the horizontal and vertical force components. The user is encouraged to share their equations for better assistance. The thread highlights the complexities of applying theoretical concepts to practical problems in electricity.
benji
Messages
48
Reaction score
0
So I thought I understood this electricity stuff pretty well--I've read through the chapter once in full and skimmed over it a couple times. I've studied all the examples and still my problems aren't coming out correct. Here is one problem in particular that is giving me a lot of trouble:

A small sperical insulator of mass 8.00X10^-2 kg and charge +0.600 mC is hung by a thin wire of negligible mass. A charge of -0.900 mC is held 0.150 m away from the spere and directly to the right of it, so the wire makes an angle [theta] with the vertical. Find (a) the angle [theta] and (b) the tension in the wire.

What I did with this problem is draw a free-body diagram for the forces that act upon the sphere attatched to the string. I found the force of gravity by simply using F=mg, so I have the left side of the right triangle. Then I solved for the electrical force between the two spheres by using F=(k*q1*q2)/(r^2). That gives me the bottom of the right triangle. So shouldn't I just be able to use simple trig to find the hypotenuse of the triangle, thus finding tension on the string? I did this and my answer came out to be 0.615 N--the correct answer is 0.813 N. Where did I go wrong? I've checked and re-checked my math and I still can't figure out why. So that was part (b), for part (a) of the problem I just used trig--inverse tangent multiplied by the bottom side of the trianle over the tension. For this answer I'm WAY off--I get -2.3X10^-21 degrees when the correct answer is 15.4 degrees.

So I know I wrote a little novel here, but I could really use the help!

Thanks.
 
Physics news on Phys.org
I don't know if this is the problem, but did you keep in mind that the electrical force will increase as the ball swings closer to the charge?
 
Have you tried using Newton's second law for the horizontal and vertical components of force on the sphere?

\Sigma F_x = ma_x

\Sigma F_y = ma_y

its hard to tell what went wrong because we can't see your equations, post any work you've done so far
 
Last edited:
I think I'll just ask about this one tomorrow in class, thanks anyways though. I should have just scanned my paper ;) .
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top