I need to find Lim (x->0) arcsin(2x)/arcsin(3x)(adsbygoogle = window.adsbygoogle || []).push({});

I can do a substitution

arcsin(2x) = y => 2x = sin(y)

and get arcsin(sin(y)) for the nominator, which is equal to y.

However, for the denominator i get arcsin(3/2 sin(y)) which I'm not sure what to do with.

Am I on the right path?

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# I need to find Lim (x->0) arcsin(2x)/arcsin(3x) by substitution

**Physics Forums | Science Articles, Homework Help, Discussion**