oliver.smith8 Messages 3 Reaction score 0 Thread starter Apr 28, 2010 #1 how does [tex]\frac{1/a -1/b}{1/a+1/b}= \frac{b-a}{b+a}[/tex] Ive been trying to work this out for ages thanks
how does [tex]\frac{1/a -1/b}{1/a+1/b}= \frac{b-a}{b+a}[/tex] Ive been trying to work this out for ages thanks
Tac-Tics Messages 816 Reaction score 7 Apr 28, 2010 #2 It's simple algebra. Here's a few hints. The right hand side, as given, is this: [tex]\frac{\frac{1}{a} - \frac{1}{b}}{\frac{1}{a} + \frac{1}{b}}[/tex] But this can be written more clearly as: [tex](\frac{1}{a} - \frac{1}{b})(\frac{1}{a} + \frac{1}{b})^{-1}[/tex] From there, apply algebraic operations to this expression until it equals the right hand side.
It's simple algebra. Here's a few hints. The right hand side, as given, is this: [tex]\frac{\frac{1}{a} - \frac{1}{b}}{\frac{1}{a} + \frac{1}{b}}[/tex] But this can be written more clearly as: [tex](\frac{1}{a} - \frac{1}{b})(\frac{1}{a} + \frac{1}{b})^{-1}[/tex] From there, apply algebraic operations to this expression until it equals the right hand side.
Gigasoft Messages 59 Reaction score 0 Apr 28, 2010 #3 Think about what value you need to multiply the left hand side with to make it equal the right hand side.
Think about what value you need to multiply the left hand side with to make it equal the right hand side.
elect_eng Messages 372 Reaction score 2 Apr 28, 2010 #4 Multiply by ab in both the numerator and the denominator. This is multiplying by one.