I think this is simple but I just cant work out how

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how does [tex]\frac{1/a -1/b}{1/a+1/b}= \frac{b-a}{b+a}[/tex]

Ive been trying to work this out for ages

thanks
 
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It's simple algebra. Here's a few hints.

The right hand side, as given, is this:

[tex]\frac{\frac{1}{a} - \frac{1}{b}}{\frac{1}{a} + \frac{1}{b}}[/tex]

But this can be written more clearly as:

[tex](\frac{1}{a} - \frac{1}{b})(\frac{1}{a} + \frac{1}{b})^{-1}[/tex]

From there, apply algebraic operations to this expression until it equals the right hand side.
 
Think about what value you need to multiply the left hand side with to make it equal the right hand side.
 
Multiply by ab in both the numerator and the denominator. This is multiplying by one.