I think this is simple but I just cant work out how

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In summary, to solve the equation \frac{1/a -1/b}{1/a+1/b}= \frac{b-a}{b+a}, you can simplify the right hand side to (\frac{1}{a} - \frac{1}{b})(\frac{1}{a} + \frac{1}{b})^{-1} and then multiply both the numerator and denominator by ab to get the solution.
  • #1
oliver.smith8
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how does [tex]\frac{1/a -1/b}{1/a+1/b}= \frac{b-a}{b+a}[/tex]

Ive been trying to work this out for ages

thanks
 
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  • #2
It's simple algebra. Here's a few hints.

The right hand side, as given, is this:

[tex]\frac{\frac{1}{a} - \frac{1}{b}}{\frac{1}{a} + \frac{1}{b}}[/tex]

But this can be written more clearly as:

[tex](\frac{1}{a} - \frac{1}{b})(\frac{1}{a} + \frac{1}{b})^{-1}[/tex]

From there, apply algebraic operations to this expression until it equals the right hand side.
 
  • #3
Think about what value you need to multiply the left hand side with to make it equal the right hand side.
 
  • #4
Multiply by ab in both the numerator and the denominator. This is multiplying by one.
 

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