I think this is simple but I just cant work out how

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Homework Help Overview

The problem involves simplifying the expression \(\frac{1/a -1/b}{1/a+1/b}\) and showing its equivalence to \(\frac{b-a}{b+a}\). The subject area pertains to algebraic manipulation and rational expressions.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss algebraic techniques for simplifying the expression, including rewriting the terms and considering multiplicative factors. Some participants suggest specific algebraic operations, while others question what adjustments are necessary to achieve the desired equivalence.

Discussion Status

There are various hints and suggestions being offered regarding algebraic manipulation. Participants are exploring different methods to approach the problem, but there is no explicit consensus on a single method or solution path at this time.

Contextual Notes

Participants are working within the constraints of a homework problem, which may limit the information available for discussion and the approaches that can be taken.

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how does [tex]\frac{1/a -1/b}{1/a+1/b}= \frac{b-a}{b+a}[/tex]

Ive been trying to work this out for ages

thanks
 
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It's simple algebra. Here's a few hints.

The right hand side, as given, is this:

[tex]\frac{\frac{1}{a} - \frac{1}{b}}{\frac{1}{a} + \frac{1}{b}}[/tex]

But this can be written more clearly as:

[tex](\frac{1}{a} - \frac{1}{b})(\frac{1}{a} + \frac{1}{b})^{-1}[/tex]

From there, apply algebraic operations to this expression until it equals the right hand side.
 
Think about what value you need to multiply the left hand side with to make it equal the right hand side.
 
Multiply by ab in both the numerator and the denominator. This is multiplying by one.
 

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