# Ice cubes added to pool to make it cool enough

• confused1
In summary, a physics grad student filled a child's plastic swimming pool with 200 liters of water at 25 C. He then added ice cubes from his refrigerator, each with a mass of 30 g, until the temperature stabilized at 16 C. To determine how many ice cubes were needed, the student used the specific heat of water (1.0 cal/g C) to calculate the heat lost by the water and the specific heat of ice (0.5 cal/g C) and latent heat of fusion of water (80 cal/g) to calculate the heat gained by the ice cubes. The number of ice cubes added was determined by dividing the heat lost by the water by the heat gained by each ice cube.
confused1
Trying to beat the heat of summer, a physics grad student went to the local toy store and purchased a child's plastic swimming pool. Upon returning home, he filled it with 200 liters of water at 25 C. Realizing that the water would probably not be cool enough, he threw ice cubes from his refrigerator, each of mass 30 g, into the pool. (The ice cubes were originally at 0 C.) He continued to add ice cubes until the temperature stabilized at 16 C. He then got in the pool.

The density of water is 1000 kg/m3, the specific heat of water is 1.0 cal/g C, the specific heat of ice is 0.5 cal/g C, and the latent heat of fusion of water is 80 cal/g.

How many ice cubes did he add to the pool to get the temperature to 16 C? (Consider the pool and ice cubes an isolated system.)

HELP: Heat lost by water = heat gained by ice cubes. No heat is lost to the surroundings.

HELP: Since the water (subsystem 1) is at a higher temperature, heat will be lost to the ice cubes (subsystem 2). Calculate the heat H that the water gave up from 25 C to 16 C; calculate the heat h that each ice cube gained from 0 C to 16 C including melting. Then the number of ice cubes equals H/h.

Last edited:
Using the specific heat of water, calculate how many calories will need to be transferred from the 200 liters of water (convert liters to grams... i think 1 ml is 1 gram of water... not sure though) the 25 - 16 = 9C the guy wants.

Then determine how many calories each ice cube adds by using the latent heat of fusion of water plus the specific heat of water to reach teh 16C. Then figure out how many ice cubes undergoing this process will be required to make up the 9C in teh 200l of water.

To determine the number of ice cubes added, we need to first calculate the total heat lost by the water and the total heat gained by the ice cubes. This can be done using the formula Q = mcΔT, where Q is the heat, m is the mass, c is the specific heat, and ΔT is the change in temperature.

For the water, the initial temperature is 25 C and the final temperature is 16 C, so ΔT = 9 C. The mass of the water is given as 200 liters, which is equivalent to 200 kg. The specific heat of water is 1.0 cal/g C, so we need to convert the mass to grams. This gives us a total heat lost by the water of Q = (200,000 g)(1.0 cal/g C)(9 C) = 1,800,000 cal.

For the ice cubes, we need to consider both the change in temperature and the melting of the ice. The ice cubes start at 0 C and end at 16 C, so ΔT = 16 C. The mass of each ice cube is given as 30 g. The specific heat of ice is 0.5 cal/g C, so the heat gained by each ice cube is Q = (30 g)(0.5 cal/g C)(16 C) = 240 cal.

However, we also need to consider the heat gained from the melting of the ice cubes. The latent heat of fusion of water is 80 cal/g, so the total heat gained from melting is h = (30 g)(80 cal/g) = 2,400 cal.

Now, we can calculate the number of ice cubes by dividing the total heat lost by the water (1,800,000 cal) by the total heat gained by each ice cube (240 cal + 2,400 cal = 2,640 cal). This gives us a total of 682.7 ice cubes. Since we cannot have a fraction of an ice cube, the grad student likely added 683 ice cubes to the pool in order to lower the temperature to 16 C.

## What is the purpose of adding ice cubes to a pool?

Adding ice cubes to a pool is a common method to lower the overall temperature of the pool water. This is especially useful during hot summer months when the pool water can become uncomfortably warm.

## How many ice cubes should be added to a pool?

The amount of ice cubes needed to effectively cool a pool will vary depending on the size of the pool and the desired temperature. As a general rule, it is recommended to use 1 pound of ice cubes for every 10,000 gallons of pool water.

## Can adding ice cubes damage the pool's filtration system?

No, adding ice cubes to a pool will not damage the filtration system. The ice cubes will eventually melt and become diluted in the pool water, and the filter will remove any remaining debris.

## How long will it take for the ice cubes to cool the pool?

The time it takes for the ice cubes to cool the pool will depend on the initial temperature of the pool water and the amount of ice cubes used. In general, it can take anywhere from a few hours to a full day for the pool water to reach a comfortable temperature.

## Are there any alternative methods for cooling a pool?

Yes, there are other methods for cooling a pool, such as using a pool cover to block out sunlight and prevent the water from heating up, or installing a pool chiller to actively cool the water. These methods may be more effective for larger pools or in extremely hot climates.

• Introductory Physics Homework Help
Replies
17
Views
3K
• Introductory Physics Homework Help
Replies
10
Views
2K
• Introductory Physics Homework Help
Replies
1
Views
1K
• Introductory Physics Homework Help
Replies
7
Views
8K
• Introductory Physics Homework Help
Replies
1
Views
1K
• Introductory Physics Homework Help
Replies
4
Views
2K
• Introductory Physics Homework Help
Replies
7
Views
1K
• Introductory Physics Homework Help
Replies
3
Views
1K
• Introductory Physics Homework Help
Replies
3
Views
1K
• Introductory Physics Homework Help
Replies
4
Views
6K