How Do You Calculate Moles of Water Vapor in Air Using Ideal Gas Law?

AI Thread Summary
To calculate the moles of water vapor in air using the Ideal Gas Law, the relative humidity of 55% at 30.0°C corresponds to a vapor pressure of 4200 Pa. The temperature must be converted to Kelvin, resulting in 303 K. The formula n/v = p/RT is applied, where p is the vapor pressure, R is the gas constant (8.32 J/(mol·K)), and T is the temperature in Kelvin. Using these values, the calculation yields approximately 1.67 mol/m³. Further clarification is needed on converting the results to the desired units.
owura143
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The relative humidity is 55% on a day when the temperature is 30.0°C. Using the graph below, determine the number of moles of water vapor per cubic meter of air.


on the graph, Vapor pressure of water is on the y-axis and temperature on the x-axis 30C cordinates with 4200 Pa of water vapor.


This how i tried to sove it.

Since 30 corresponds to 4200 Pa

T in Kelvin =303
n/v = p/RT
=4200/(8.32 x 303)
= 1.67
 
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I need help with this same problem...

http://www.webassign.net/CJ/12_76.gif

That is the graph, if anyone can help.

EDIT... I really don't know where to start at all. I tried to do it (almost) the same way as owura, but I couldn't figure it out how to find it in "mol/m^3".
 
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