I Identical Particle States in a Unidimensional Box

JamesHG
Messages
4
Reaction score
0
I have an "unidimensional" box with two identical particles in. My question is , Does it matter in which total spin state is my total function? I mean , if it is a singlet or triplet , one is antisymmetrical and the other is symmetrical, but I only integrate the function in the spatial coordinates, so any answer?
 
Physics news on Phys.org
JamesHG said:
I have an "unidimensional" box with two identical particles in. My question is , Does it matter in which total spin state is my total function? I mean , if it is a singlet or triplet , one is antisymmetrical and the other is symmetrical, but I only integrate the function in the spatial coordinates, so any answer?
It matters. The total wave function, which includes both position and spin, must be antisymmetric under exchange of particles. Thus, the position must be symmetric if the spin is in the singlet state and antisymmetric if the spin is in the triplet state.
 
If the particles are non-interacting, you can easily write down the wave-function. Take ##x_2\ge x_1## and figure out the boundary condition for ##x_2=x_1##.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!
Back
Top