Identifying Forces and Directions in Torque and Equilibrium

AI Thread Summary
The discussion centers on understanding torque and equilibrium, particularly in relation to a tripod's support of an object's weight. Each leg of the tripod is required to support one-third of the total weight, with the force acting vertically. The user is seeking assistance in drawing a free body diagram and identifying the forces at play, specifically starting from the bottom of one leg. Clarification on the directions of these forces is also requested. Overall, the focus is on grasping the fundamental concepts of torque and equilibrium in this context.
Intr3pid
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hello everyone

I recently started learning about torque and I'm having a lot of trouble with the first 2 questions. Can someone help me out with the first two questions?

btw, I don't quite understand how to draw the free body diagram for the first question.

PS the questions are located on the attachments
 

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Try considering just one 'leg' of the tripod
 
can someone help me out please?

I'm really stuck.
 
For the first one:
Each leg of the tripod needs to support one third of the object's weight. Keep in mind that this force is being applied strictly vertical
 
I still don't quite get it.
 
Lets start at the bottom of one leg. What forces do you indentify and in what direction are they?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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