If an object is moving in a straight line and it has uniform motion

AI Thread Summary
An object moving in a straight line with uniform motion does indeed have uniform velocity, as uniform motion implies constant speed and direction. However, discrepancies in lab results may arise from human error, leading to confusion about the relationship between uniform motion and velocity. The discussion highlights the importance of understanding definitions in physics versus practical observations. Clarifying whether the inquiry pertains to theoretical definitions or experimental outcomes is crucial for accurate interpretation. Ultimately, consistent definitions and careful experimentation are essential for understanding motion in physics.
zoomzoom
Messages
3
Reaction score
0
does it have uniform velocity?
 
Physics news on Phys.org
What do you think? And why?
 
I think it does because uniform motion has constant speed. But my lab results are showing otherwise... although this could be from human error. :rolleyes:
 
Are you asking about the definition of a term, or are you asking about lab tests and observations?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top