If the electron is freed up, what would be its acceleration?

In summary, the Electric Potential on an XY plane is described by the relationship V=2x^2-2y^2. The goal is to consider ONLY values in the range [0, 5] and solve the following questions: A) Depict on an XY plane three lines of equal potential V=-4V, 0V and 4V. Consider 5 ponts. X= 0, 1, 2, 3, 4, 5.B) Consider one point where x= 3m, and y= 3m. Estimate the electric field magnitude in volts per meter.C) For the same point, estimate the direction of the electric field, counting counter-clock
  • #1
dimpledur
194
0

Homework Statement


The Electric Potential on an XY plane is described by the relationship V=2x^2-2y^2. Consider ONLY values in the range [0, 5].

A) Depict on an XY plane three lines of equal potential V=-4V, 0V and 4V. Consider 5 ponts. X= 0, 1, 2, 3, 4, 5.
B) Consider one point where x= 3m, and y= 3m. Estimate the electric field magnitude in volts per meter.
C) For the same point, estimate the direction of the electric field, counting counter-clockwise from the X-axis. If an electron is placed at this point, D) what would be the direction and E) the magnitude of the force acting on it.
F) If the electron is freed up, what would be its acceleration?

The Attempt at a Solution



A) Don't need help with this.

B) For this question, I am assuming we wouldn't differentiate the the equation given since it is in terms of x and y. Would it be logical to use E=V/x where V is the potential difference between the two closest contours and x is the distance between them passing through (3, 3)?

C) For this question, I am also assuming this is merely conceptual and that there is no calculations to determine the angle. I was going to estimate 120 deg- 135 deg from the +x axis.

D) Wouldn't the electric field from an electron be insignificant relative to this field, therefore the electric field would remain in the direction it was?

E/F) Don't require help.

Thanks!
 
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  • #2
dimpledur said:

Homework Statement


The Electric Potential on an XY plane is described by the relationship V=2x^2-2y^2. Consider ONLY values in the range [0, 5].

A) Depict on an XY plane three lines of equal potential V=-4V, 0V and 4V. Consider 5 ponts. X= 0, 1, 2, 3, 4, 5.
B) Consider one point where x= 3m, and y= 3m. Estimate the electric field magnitude in volts per meter.
C) For the same point, estimate the direction of the electric field, counting counter-clockwise from the X-axis. If an electron is placed at this point, D) what would be the direction and E) the magnitude of the force acting on it.
F) If the electron is freed up, what would be its acceleration?

The Attempt at a Solution



A) Don't need help with this.

B) For this question, I am assuming we wouldn't differentiate the the equation given since it is in terms of x and y. Would it be logical to use E=V/x where V is the potential difference between the two closest contours and x is the distance between them passing through (3, 3)?

C) For this question, I am also assuming this is merely conceptual and that there is no calculations to determine the angle. I was going to estimate 120 deg- 135 deg from the +x axis.

D) Wouldn't the electric field from an electron be insignificant relative to this field, therefore the electric field would remain in the direction it was?

E/F) Don't require help.

Thanks!

B)Remember the more general relation between the electric field and the potential. The x component of the electric field is given by the derivative of V with respect to x:

[tex]E_x=\frac{dV}{dx}[/tex]

Similarly,

[tex]E_y=\frac{dV}{dy}[/tex]

C)Once you have the components of the E field vector, finding the direction should be straightforward.

D) You can check easily enough. Workout the value of the electric field from an electron, say, 1m away from the electron. In magnitude, is it much smaller or much bigger or same as the average field given by the above potential. (just roughly estimate)
 
  • #3
Could you explain A? I have a similar question and I don't understand it. thanks
 
  • #4
Thanks for the response. However, I have a bit of confusion.

Would Ex=d(2x^2)/dx = 4x

and Ey=d(-2y^2)=-4y

When doing this I get E= {12i - 12j} which doesn't really make sense. Help?


Also, for A what you have to do is set the equation equal to y. Then, plug in -4 V, and all of the x points to find the y points that go with it. You will do this for -4, 0, and 4V. Then plot the equipotential curves.
 
  • #5
Nevermind. I figured it out.
 
  • #6
I have the same question and am having trouble with C) to F)
 
  • #7
dimpledur said:
Nevermind. I figured it out.

Great!

rdmusic16 said:
I have the same question and am having trouble with C) to F)

Can you post your attempt at the solution?

Also, please post part E (the OP never mentioned what the question in part E was.)
 

Related to If the electron is freed up, what would be its acceleration?

1. What is an electron and how is it freed up?

An electron is a subatomic particle with a negative charge that is found in the outer shells of atoms. It can be freed up by gaining enough energy to overcome the attraction of the positively charged nucleus.

2. What factors affect the acceleration of a freed electron?

The acceleration of a freed electron can be affected by the strength of the electric field, the mass of the electron, and any external forces acting on it.

3. How is the acceleration of a freed electron calculated?

The acceleration of a freed electron can be calculated using the formula a = F/m, where a is the acceleration, F is the net force acting on the electron, and m is the mass of the electron.

4. Can the acceleration of a freed electron be negative?

Yes, the acceleration of a freed electron can be negative if it is moving in the opposite direction of the electric field or if there are external forces acting on it in the opposite direction.

5. What is the relationship between acceleration and velocity for a freed electron?

The acceleration of a freed electron is directly proportional to the change in velocity over time. This means that as the electron accelerates, its velocity increases or decreases depending on the direction of the acceleration.

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