If you submerge a 3cm cube of ice in cup of water, with what force

AI Thread Summary
When submerging a 3cm cube of ice in water, the forces acting on the ice include its weight and the buoyant force from the water. The calculation involves using the densities of both water and ice to determine the net force. The correct approach is to apply the equation F = ρwatergV - ρicegV, where V is the volume of the ice cube. The densities should be used appropriately: the density of water for the buoyant force and the density of ice for the weight of the ice cube. The solution confirms that the method and calculations are correct.
kthejohnster
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Homework Statement


If you submerge a 3cm cube of ice in cup of water, with what force will the ice float up to the surface


Homework Equations



ρgV, F=ma, ρgh

The Attempt at a Solution



I thought to draw free body diagram of vertical forces with mg of ice cube and ρicegAhtop surface as negative forces and positive buoyant force of ρwaterg(htop surface+.03cm)A summing to Fnet.
End up getting ρwatergV-ρicegV=F
I just want to make sure I got the right densities in right places, in other words when do you use the density of water and when do you use the density of ice?
 
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kthejohnster said:
End up getting ρwatergV-ρicegV=F

It is correct.

ehild
 

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