Find the Average Power of a 560 kg Elevator

In summary, The conversation is about finding the average power delivered by an elevator motor during a period of constant acceleration. The formula for calculating power is P=(F*d)/t, where F is the force applied, d is the distance traveled, and t is the time. The net force on the elevator can be found using Newton's Third Law and the relationship between force and acceleration. Another method is to calculate the work done by the elevator by finding its height and using the formula W=mgh, where m is the mass, g is the acceleration due to gravity, and h is the height reached. However, this method must also consider the work done to increase the kinetic energy.
  • #1
Unknown_20
7
0
Can someone please help with this? Thanks in advance.

A(n) 560 kg elevator starts from rest. It moves
upward for 4.61 s with a constant acceleration
until it reaches its cruising speed of 2.13 m/s.
The acceleration of gravity is 9.8 m/s2.
Find the average power delivered by the
elevator motor during this period. Answer in
units of kW.
 
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  • #2
What exactly have you tried to do with this problem on your own?
 
  • #3
Well, I found that the acceleration is equal to .462039 until the speed is constant. I'm not sure what steps to take from here or if I'm even on the right track.
 
  • #4
Correct so far...

Now, how do you calculate power ? What formula is there for that ?
 
  • #5
the equation is P=(F*d)/t
 
  • #6
That will work. Now what is F = ? and what is d = ? You know what t is.
 
  • #7
If I knew that I would not have asked the question.
 
  • #8
I'm trying to help you here, so it would be in your interest to simmer down.

Okay, why don't you draw the free-body diagram for the elevator ? What are the different forces acting on it ? What is the net force equal to ? And you know the mass and acceleration. Use Newton's Third Law to find the relation between the net force and the acceleration. From this, you can find the value of F.
 
  • #9
You know the final velocity, total time taken calculate the acceleration. Multiply it withh mass it will be the work done by it divide it by total time taken.
knock-knock, who's this, your answer.
Another way,
calculate the height at which it reached multiply it with mass and acc. due to gravity it will be the work done divide it wih time.
 
  • #10
aekanshchumber said:
You know the final velocity, total time taken calculate the acceleration. Multiply it withh mass it will be the work done by it divide it by total time taken.

No, mass*acceleration is not the work done. And one more thing you're forgetting here is the force needeg to bear the weight of the elevator. You must include that too.

Another way,
calculate the height at which it reached multiply it with mass and acc. due to gravity it will be the work done divide it wih time.

What about the work done to increase the kinetic energy ? If you include that, this method will work.
 
Last edited:

FAQ: Find the Average Power of a 560 kg Elevator

1. How do you calculate the average power of a 560 kg elevator?

To calculate the average power of a 560 kg elevator, you need to know the time it takes for the elevator to move from one floor to another and the distance between floors. The formula for average power is average power = work/time. Therefore, you can divide the work done by the elevator (which is the force applied to the elevator multiplied by the distance it moves) by the time it takes to complete the movement.

2. Why is it important to find the average power of a 560 kg elevator?

Knowing the average power of a 560 kg elevator is important for maintaining the elevator's efficiency and safety. It also helps in understanding the energy consumption of the elevator and can inform decisions about energy-saving measures.

3. What factors can affect the average power of a 560 kg elevator?

The average power of a 560 kg elevator can be affected by the weight of the elevator, the distance it travels, and the speed at which it moves. Other factors such as friction, air resistance, and mechanical efficiency can also impact the average power.

4. Can the average power of a 560 kg elevator vary over time?

Yes, the average power of a 560 kg elevator can vary over time. This can be due to changes in the weight of the elevator, changes in the distance it travels, or changes in the speed at which it moves. Other external factors such as weather conditions or elevator maintenance can also affect the average power.

5. How can the average power of a 560 kg elevator be optimized?

The average power of a 560 kg elevator can be optimized by reducing the weight of the elevator, minimizing the distance it travels, and increasing the efficiency of its mechanical components. Using energy-efficient technology and regular maintenance can also help in optimizing the average power of an elevator.

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