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## Homework Statement

find y' given x

^{3}+y

^{2}+x+y=2

## Homework Equations

## The Attempt at a Solution

dy/dx=3x

^{2}+2y(y')+1+y'

I know thats wrong because my 89 gives it as y'=(-3x

^{2}+1)/(2y+1), I don't know how to get there though and what happened to the =2.

Thanks