Impulse and Momentum of two cars

AI Thread Summary
The discussion revolves around calculating the total momentum of two identical cars, each with a mass of 1350 kg traveling at 25.0 m/s. Participants suggest breaking down the momentum into x and y components to find the resultant momentum. There is confusion regarding how to split momentum since it is a vector quantity. Additionally, the discussion touches on determining the net average force from a momentum-time graph, with a request for clarification on how to approach this problem. The conversation highlights the need for understanding vector components in momentum calculations.
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Homework Statement


Two identical cars (m = 1350 kg) are traveling at the same speed of 25.0 m/s. They are moving in the directions shown in the drawing. What is the magnitude of the total momentum of the two cars?
img:http://higheredbcs.wiley.com/legacy...ics/sat_c07/sat_c07_q1_03/sat_c07_q1_03_1.gif


A particle is moving along the +x axis, and the graph shows its momentum p as a function of time t. What is the magnitude of the net average force in regions A . Give your answer to two significant figures, e.g., 6.3 or 0.72.
img: http://higheredbcs.wiley.com/legacy...ics/sat_c07/sat_c07_q1_08/sat_c07_q1_08_1.gif

Homework Equations



i don't know I'm confused.

The Attempt at a Solution



please help me.thank you very much!
 
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For the first one, try splitting the momenta into x and y components and then finding the resultant x and y momenta
 
how can i split the momentum?hoho confused
 
Momentum is a vector.
 

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