Solving Impulse Graph Questions: Velocity Calculation & Solution Check

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The discussion focuses on solving impulse graph questions related to velocity calculations in a physics homework problem. Participants clarify the Impulse-Momentum Theorem, emphasizing that an object's change in momentum equals the net impulse acting on it. The main confusion arises around calculating the final velocity at the end of a 1.20-second impact, given an initial velocity and the forces represented in a graph. After reviewing the calculations, it is confirmed that the initial momentum should be adjusted by the impulse to find the final velocity. The final velocity is determined to be 1 m/s after the impact.
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Homework Statement





Homework Equations


fnet(delta t) = m (delta v)


The Attempt at a Solution


I need some help on question b ASAP (i'm not sure what the question means when it says find the velocity AT THE END of the 1.20 sec impact)
and i would like for someone to check if I've answered question A correctly
 

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A looks right.And for part B, the problem seems set up where that graph of F vs. t is the forces acting on the player for 1.2s. It gives you an initial velocity, and asks what those forces (so the impulse that you already calculated) make her final velocity.
 
Nitrate said:

Homework Statement



Homework Equations


fnet(delta t) = m (delta v)

The Attempt at a Solution


I need some help on question b ASAP (i'm not sure what the question means when it says find the velocity AT THE END of the 1.20 sec impact)
and i would like for someone to check if I've answered question A correctly
attachment.php?attachmentid=48101&d=1339036908.png


What does the Impulse - Momentum Theorem say ?
 
SammyS said:
attachment.php?attachmentid=48101&d=1339036908.png


What does the Impulse - Momentum Theorem say ?

not sure
 
The impulse is defined as the integral of a force with respect to time. Wiki "impulse" if you need more help
 
Nitrate said:
not sure
Momentum Theorem is something like:

An object's change in momentum is equal to the net impulse on the object.


Look it up to be sure!
 
i believe I've found the integral in part A but i don't know what part b means by "find the velocity at 1.20 seconds"

i've got the following information compiled for part b)
fnet(delta t) = m (delta v)
delta t = 1.20 seconds
Fnet = ?
m = 60 kg
vi = 7.0 m/s
vf = ?

my problem is that i don't know what fnet is.
 
I=Δp

so you know your initial momentum. Now find the final momentum, using the above fact. :biggrin:
 
Nitrate said:
i've got the following information compiled for part b)
fnet(delta t) = m (delta v)

...

my problem is that i don't know what fnet is.

What's the name for fnet(delta t)?
 
  • #10
Villyer said:
What's the name for fnet(delta t)?

impulse. however, i don't know if i did part A right and i don't know if they want me to use all the information in question B... and i do not understand what they mean by AFTER 1.20 seconds
 
  • #11
Nitrate said:
... and i do not understand what they mean by AFTER 1.20 seconds

Look at the graph again .
 
  • #12
You have an initial momentum - think about how that impulse ( change in momentum) will change the player's speed. (you're looking for pf)
 
  • #13
Nitrate said:
impulse. however, i don't know if i did part A right and i don't know if they want me to use all the information in question B... and i do not understand what they mean by AFTER 1.20 seconds

Your part A was right.

And it just means that at t = 0 the velocity is 7, what is the velocity at t = 1.2?
 
  • #14
i think i got it
-360 n*s = 60(vf-7)
-6=vf-7
vf=1 m/s
?
 
  • #15
correct
 

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