How Do You Solve Basic Impulse-Momentum Physics Problems?

  • Thread starter wellgrin
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In summary: N. 1 N = 1 kgm/s^2. So if the mass of the bullet is 0.005kg, then the force applied is m*a = 0.005*200000 = 1000 N. The time taken for the acceleration is not given. So we cannot find the time. The impulse of the force is 1000N*0.08m=80N.sec. 1 N.s = 1 kgm/s, so the impulse is equal to the change in momentum. So the change in momentum = 80 kgm/s. In summary,
  • #1
wellgrin
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1. A bullet with a mass of 0.0050kg and moving with a speed of 400 m/s penetrates a distance of 0.08m into a wooden block firmly attached to the earth. Assume that the force that stops it is constant.

Compute for:
a) The acceleration of the bullet
b) The accelerating force
c) The time of the acceleration
d) The impulse of the force

2. A baseball has a mass of 0.200kg.
a) If the velocity of a pitched ball has a magnitude of 35m/s in the opposite direction, find the change in momentum of the ball and the impulse applied to it by the bat.
b) If the ball remains in contact with the bat for 2.0x10^-3 sec, find the average force applied by the bat.

3.) A ball with a mass of 0.40kg is thrown against a brick wall. It hits the wall moving horizontally to the left at 30m/s and it rebounds horizontally to the right at 20 m/s. Find the impulse of the force exerted on the ball by the wall. If the during the impact for 0.010sec, find the average force on the ball during the impact.





F = ma
a = v2-v1/t2-t1




I really don't have an idea how to solve this problems. Please help me. :cry:
 
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  • #2
What is the relation between the initial velocity, final velocity and the dispalcemect?
What is the work done by the bullet on the wooden block?
what is the formula for momentum?
 
  • #3
rl.bhat said:
What is the relation between the initial velocity, final velocity and the dispalcemect?
What is the work done by the bullet on the wooden block?
what is the formula for momentum?

1. I really don't know
2. It is not given
3. The formula for momentum is p = mv..
 
  • #4
1. v^2 -u^2 = 2as
2.Work done by the bullet = F*s = loss of kinetic energy of the bullet = 1/2mv^2
 
  • #5
rl.bhat said:
1. v^2 -u^2 = 2as
2.Work done by the bullet = F*s = loss of kinetic energy of the bullet = 1/2mv^2

v^2-u^2=2as?? I can't apply it since I don't have initial and final velocity.. OMG! please somebody help. I need this in three hours.
 
Last edited:
  • #6
Initial velocity of the bullet is 400m/s. Finally it stops in the block. So the final velocity =0. s = 0.08 m.
 

1. What is the equation for calculating impulse in an impulse-momentum problem?

The equation for calculating impulse in an impulse-momentum problem is impulse = force x time interval (J = FΔt). This equation represents the change in momentum over a specific time period, where impulse is measured in Newton-seconds (N·s) and force is measured in Newtons (N).

2. How do you calculate the change in momentum for an object in an impulse-momentum problem?

The change in momentum for an object can be calculated by using the equation change in momentum = mass x change in velocity (Δp = mΔv). This equation takes into account the mass of the object and the change in its velocity over a certain time period, where momentum is measured in kilogram-meters per second (kg·m/s).

3. What is the relationship between force and momentum in an impulse-momentum problem?

The relationship between force and momentum in an impulse-momentum problem can be described by Newton's Second Law, which states that force = mass x acceleration (F = ma). This means that the force applied to an object will cause a change in its momentum, either by increasing or decreasing its velocity.

4. How does the duration of an impulse affect the change in momentum?

The duration of an impulse directly affects the change in momentum. The longer the duration of the impulse, the greater the change in momentum. This is because a longer duration allows for a smaller force to be applied, resulting in a smaller change in velocity. On the other hand, a shorter duration of impulse requires a larger force, resulting in a larger change in velocity and hence a greater change in momentum.

5. Can you give an example of an impulse-momentum problem in real life?

One example of an impulse-momentum problem in real life is a car crash. When a car crashes into an object, the force of the impact causes a change in the car's momentum. This change in momentum can be calculated by using the mass of the car and the change in its velocity. The longer the duration of the impact, the less severe the change in momentum will be, potentially reducing the damage to the car and its occupants.

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