Impulse Problem: Find Mass, Height & Impulse

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In summary, the ball with a mass of .110 kg was dropped from a height of 1.25 m and rebounded to a height of .800 m. The impulse given to the ball by the floor can be calculated using the equation J = ΣFΔt or J = Δp, where J is the impulse, ΣF is the sum of forces, Δt is the change in time, and Δp is the change in momentum. The exact value of J can be found by taking the integral of force over time, with an infinite number of infinitesimal time intervals. The given attempt at a solution uses the incorrect symbol for impulse and needs to be modified to accurately represent the impulse calculation.
  • #1
chocolatelover
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Homework Statement


A ball of mass .110 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of .800 m. What impulse was given to the ball by the floor?


Homework Equations




I=ΣFΔt
Δp=I

The Attempt at a Solution



Could someone please tell me if this is the correct formula?

Thank you very much
 
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  • #2
Hi chocolatelover! Both of your equations look right but need some minor tweaking.

For starters (I have no clue why, but...) the symbol for impulse is a capitol J.

So J = Δp for instance.

Your first equation should be extended a bit more.

J = ΣFΔt would give you an approximation for impulse however if you wanted the exact value of J you would need to make Δt -> 0, and sum up an infinite number tiny bits force.

A more concrete definition would be [tex]J = \int_{t_i}^{t_f}{F dt}[/tex]
 
  • #3
Thank you very much

Does this look right?
integral from 1.25 to .800 (.110kg)(9.8m/s^2)dt

=.8624-1.35
=-.4876

Thank you very much
 

1. How do you calculate mass in an impulse problem?

In an impulse problem, mass can be calculated by dividing the impulse (change in momentum) by the change in velocity, or by dividing the force applied by the acceleration. The formula for mass in an impulse problem is: m = Δp/Δv = F/Δa.

2. How do you find the height in an impulse problem?

The height in an impulse problem can be found by using the formula: h = (1/2)gt^2, where g is the acceleration due to gravity (9.8 m/s^2) and t is the time interval. This formula assumes that the object was initially at rest and that there is no air resistance.

3. What is impulse in physics?

In physics, impulse is a measure of the change in an object's momentum over a certain period of time. It is equal to the force applied to the object multiplied by the time interval during which the force was applied. The unit of impulse is the Newton-second (N-s) in the SI system.

4. Can you find the mass and height in an impulse problem without knowing the force?

Yes, it is possible to find the mass and height in an impulse problem without knowing the force applied. This can be done by using the formula for impulse (J = FΔt) and the equations for mass (m = Δp/Δv) and height (h = (1/2)gt^2). However, it is usually easier to solve an impulse problem if the force is known.

5. How is impulse related to Newton's laws of motion?

Impulse is related to Newton's laws of motion through the second law, which states that the net force applied to an object is equal to its mass multiplied by its acceleration (F = ma). This can be rewritten as FΔt = mΔv, which is the formula for impulse. Therefore, impulse can be used to analyze an object's motion and determine the force acting on it.

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