Originally posted by Vosh
The way it was explained to me was like this: You have a sea of electrons. A voltage is applied. Now, I gather this means that there is an electric field throughout (or just on the surface of) the wire? So with DC, as you get from a battery, the electric field rises to, say, 9 volts and stays there (as oppose to AC where the strength of the electric field rises and falls periodically). Now, I was given to understand that it isn't the electrons which travel at (near enough, anyway) light speed, it is the wave which propagates through the sea of electrons which travels so fast (which I am able to believe by visualizing that tube of ping pong balls where you shove one ball in one end and another one instantly pops out the other end, the energy of the first one reached the end of the tube that fast while the actual balls didn't move so fast -- pardon me for going excruciatingly slow with this). That is the picture I have so far, but I still don't get it. When I run a mental model, I see the electric field appear along the wire. So, with the DC circuit, there is a constant e field (I forget the other way it's designated now... some letter...). Ok, so when I asked about this I was told to imagine the waves of energy in the DC circuit as on long wave, one that was so long that it looked like a horizontal line. Unfortunately, that didn't help me. I guess I slammed up against my IQ ceiling, something for which I wish I had a dime of every occurance! It's easy enough to see AC waves; voltage going up and then having to go down and then up again. But with DC there is just one wave where you rise up to our 9 volts and stay there until falling again when the battery is disconnected. But I have trouble seeing how this one long wave moves energy through the ciruit. In my mental model I can see one wave when the battery is connected and then all I can see are the electrons having to poke their way through the wire but with no waves propagating through them at lightning speed. Maybe I'm visualizing this incorrectly. Thinking of the circuit as a bike wheel, where the brake is like a resistor, slowing down the entire circuit, not just the part it's applied to, if I push on it periodically, that is like AC and if I apply constant pushing, say with contact with another wheel, then that is like DC. Perhaps that tube of ping pong balls really is more useful (now I come to think of it after sitting here not typing for a few minutes). If I push in one end periodically, with varying pressure, that is like AC, but if I somehow apply constant pressure, a constant supply of pingpong balls, I guess you could say, then that is like DC. So the energy that is traveling through the circuit at lightning speed, is that the electric field that is being referred to? Voltage is what travels through the wire at lightning speed? And what heats the bulb? I've heard that it isn't really resistance caused by the electrons. The way I've heard it described goes; it is the energy coming down both wires, from the neg. and pos. poles, like having two slinkies stretched from both hands and you pull on one and make a wave travel out towards the end and you push on the other and a wave also travels from you out towards the bulb! Energy dives into the bulb from both sides (even though current is going in one direction). That's how it was explained to me but I still don't get exactly what is lighting the bulb. I know that all light is caused by electrons jumping and then falling back into their original orbits. But how is that being made to happen?
Thanks for your efforts. I grasp voltage, etc. I know the real energy to do "work" is the flow of electrons and the voltage (force) applied to make them move. What I don't get is where the electrons come from because the electrons just keep coming in a seemingly endless stream.
Many many thanks.