Increase in speed, increase in energy

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SUMMARY

The discussion centers on the kinetic energy of a 5 kg object accelerating from 5 m/s to 10 m/s. At point A, the kinetic energy is calculated as 62.5 J, while at point B, it increases to 250 J. The increase in kinetic energy is attributed to the formula 0.5mv², demonstrating that higher speeds result in greater kinetic energy. Additionally, the conversation highlights that in practical scenarios, other forms of energy must decrease to provide the necessary energy for acceleration.

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MechaMZ
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Homework Statement


an 5kg object speed up from 5m/s(point A) to 10m/s(point B)

at point A, the energy is 0.5mv2 = 0.5(5)(5)2 = 62.5J
at point B, the energy is 0.5mv2 = 0.5(5)(10)2 = 250J

I don't not sure why the energy in the object is increased when it speeds up from point A to point B. suppose the energy in the object should be taken up to increase it's speed isn't?

or my concept is wrong?
 
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You have calculated the kinetic energy, the energy due to speed. The greater the speed, the greater the kinetic energy.

In a real situation some other type of energy would have to decrease to free up the energy needed to increase the speed.
 

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