Indeoendent current source in series with a resistor

AI Thread Summary
To find node voltages using nodal analysis with an independent current source in series with a resistor, the correct expression for the current in that branch is indeed (V1 - V2)/R + I, where I is the current from the independent source. However, it's important to note that the current through the current source remains constant at I, meaning the current through the resistor is also I. This means that the voltage across the resistor can be expressed as I * R. Understanding this relationship is crucial for correctly applying nodal analysis in this scenario. Properly accounting for the current source's behavior will lead to accurate node voltage calculations.
EEngineeruic
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Guys, this seems very trivial yet I can not come to the correct answer and I've searched everywhere.

I am asked to find the node voltages using nodal analysis. The trouble is I don't know how to express a current in a brach between 2 unknown voltages where there is an independent current source in series with a resistor.

I think it should be

(V1-V2)/R +I ; for that specific branch, where I is the independent current source in that branch.

Can somebody verify that? Please
 
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EEngineeruic said:
Guys, this seems very trivial yet I can not come to the correct answer and I've searched everywhere.

I am asked to find the node voltages using nodal analysis. The trouble is I don't know how to express a current in a brach between 2 unknown voltages where there is an independent current source in series with a resistor.

I think it should be

(V1-V2)/R +I ; for that specific branch, where I is the independent current source in that branch.

Can somebody verify that? Please

The current through the current source is always I. That's why it's a current source. The current through anything in series with it is also always I.
 
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