Induced current and force on circular loop in varying magnetic field

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The discussion centers on the behavior of induced current and force in a circular loop within a varying magnetic field. It is asserted that the direction of the induced current remains anticlockwise, opposing the change in the magnetic field as per Lenz's law. However, a clarification is made that the induced current opposes the change in the magnetic field, not the field itself. Additionally, it is concluded that the net force on the loop is zero due to symmetry, as equal and opposite forces cancel each other out. Overall, the answers provided are deemed correct, with some corrections on the explanations regarding Lenz's law.
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Homework Statement
A circular loop of radius r and resistance R is placed in magnetic field given by ##B(r,t)=B_o\left(1-\frac{r}{R_o}\right)e^{kt}## where ##B_o, ~k ~\text{and} ~R_o## are positive constant and ##r\leq R_o##
a) Describe qualitatively how the direction of the induced current changes
b) Find the net force experienced by the loop
Relevant Equations
##F=\int I d\vec l \times \vec B##

Faraday and Lenz Law
a) I don't think the direction of the induced current will change. Based on Lenz law, the circular loop will produce current that will oppose the varying magnetic field. Let's assume the direction of the varying magnetic field is into the page and the plane of the circular loop is perpendicular to the magnetic field so the direction of the induced current will be anticlockwise and will stay anticlockwise.

b) I think the net force will be zero due to symmetry since the opposite part of the wire will experience equal force but in opposite direction so they will cancel out

Are my answers correct? Thanks
 
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Is there any information about the direction of the magnetic field?
How is the loop oriented in the magnetic field?
Where is the center of the loop located in the magnetic field?
Was a diagram provided with this problem?
 
TSny said:
Is there any information about the direction of the magnetic field?
How is the loop oriented in the magnetic field?
Where is the center of the loop located in the magnetic field?
Was a diagram provided with this problem?
There is no diagram and no information about all of these. The question in ##1 is all of it.

I assume it will be like this:
1743467519382.png
 
songoku said:
a) I don't think the direction of the induced current will change. Based on Lenz law, the circular loop will produce current that will oppose the varying magnetic field. Let's assume the direction of the varying magnetic field is into the page and the plane of the circular loop is perpendicular to the magnetic field so the direction of the induced current will be anticlockwise and will stay anticlockwise.
The answer is correct, but the explanation is wrong. Your statement that the induced current generates a magnetic field which opposes the initial magnetic field is not correct. Lenz’s law states that the induced current generates a magnetic field which opposes the change of the initial magnetic field.

songoku said:
b) I think the net force will be zero due to symmetry since the opposite part of the wire will experience equal force but in opposite direction so they will cancel out
The answer is correct and the explanation is correct.
 
Thank you very much TSny and Gavran
 
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Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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