Induced emf between theh ends of an antenna

Click For Summary
SUMMARY

The discussion centers on calculating the induced electromotive force (emf) between the ends of a vertical radio antenna, measuring 85 cm, as it moves through the Earth's magnetic field while traveling east at 25 m/s. The relevant equation used is E = Bvl, where B is the magnetic field strength (5.9 x 10-5 T), v is the velocity (25 m/s), and l is the length of the antenna (0.85 m). The correct angle to use in the calculation is crucial; the component of the magnetic field perpendicular to the antenna must be determined to accurately compute the induced emf, which was found to be approximately 1.19 mV.

PREREQUISITES
  • Understanding of electromagnetic induction principles
  • Familiarity with the formula E = Bvl
  • Knowledge of vector components in magnetic fields
  • Basic physics of antennas and their operation
NEXT STEPS
  • Study the concept of magnetic field components and their effects on induced emf
  • Learn about the right-hand rule in electromagnetism
  • Explore the effects of antenna orientation on signal reception
  • Investigate practical applications of induced emf in radio technology
USEFUL FOR

Physics students, electrical engineers, and anyone interested in the principles of electromagnetism and antenna design.

mike1234
Messages
5
Reaction score
0

Homework Statement


A car with a vertical radio antenna 85cm long drives due east 25 m/s. The Earth's magnetic field at this location has a magnitude of 5.9 * 10-5 T and points northward, 72 degrees below the horizontal. a) Is the top or the bottom of the antenna at the higher potential? b) Find the induced emf between the ends of the antenna


Homework Equations


E=Bvl


The Attempt at a Solution



I started with E=Bvl where E=5.9 *10-5T *(cos 18 or 108 not sure)* 25m/s * .85m and get a value of 1.19mV with cos 18. however not sure should I use 108 instead but don't know the reasoning help someone
 
Physics news on Phys.org
does no one know the answer to this question
 
Hint: To use that formula, you need the component of B perpendicular to the antenna.
 

Similar threads

Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 2 ·
Replies
2
Views
14K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 9 ·
Replies
9
Views
7K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
38
Views
7K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
5
Views
10K