How Is Current Induced in a Multi-Turn Coil with Changing Magnetic Field?

AI Thread Summary
The discussion focuses on calculating the average current induced in a coil with 253 turns as a magnetic field decreases from 2.2T to 0.0T over 0.33 seconds. The initial attempt at solving the problem used the formula for EMF, but the user received an incorrect answer. It was clarified that the EMF calculated should account for the number of turns in the coil, leading to the total flux linkage being the product of the magnetic field, area, and number of turns. The correct approach involves multiplying the induced EMF by the number of turns before applying Ohm's law to find the current. Understanding the relationship between the number of turns and the induced EMF is crucial for solving the problem accurately.
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Homework Statement



A coil with 253 turns of wire, a total resistance of 28 Ohms, and a cross-section area of 0.36m^2 is positioned in a plane perpendicular to the field of a powerful electromagnet.
What average current is induced in the coil during the 0.33s that the magnetic field drops from 2.2T to 0.0T? Answer in units of A.


Homework Equations



E = BA / t
V = IR

The Attempt at a Solution



EMF = Change in B * Area / time
= (2.2 * .36) / .33

I plug that into V = IR

V = IR
[(2.2 * .36) / .33] = I * 28 Ohms
I = [(2.2 * .36) / .33] / 28 = 0.0857142857A

However I get the wrong answer.
I think it has something to do with the 253 coils of wire but I'm not sure.
Any help is appreciated.
 
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Yes, the emf you calculate is induced in each coil of wire, so the total flux linkage at the start is BAN where N is the nuber of turns.
 

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