Engineering Induction Motor Problem, How to find Rc

AI Thread Summary
The discussion revolves around calculating parameters for a three-phase induction motor, specifically focusing on determining the core resistance (Rc) and its impact on line current, power factor, shaft torque, and efficiency. Participants express uncertainty about how to incorporate core losses, which total 262 W, into their calculations without Rc. It is suggested that Rc can be neglected in the equivalent circuit after accounting for core losses separately. The formula for line current, IL = Vphase/Zeq, is highlighted, with emphasis on the need for the equivalent impedance. The conversation emphasizes the importance of approximations in solving the problem effectively.
TheRedDevil18
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Homework Statement


A three phase 220 V , 60 Hz, six poles 10 hp induction motor has the following circuit. Parameters on a per basis referred to the stator:
Rs = 0.334 Ω,
R’R = 0.147 Ω,
Xs = 0.498 Ω
X’R = 0.224 Ω ,
Xm = 12.6 Ω
The rotational losses including the core losses amount to 262 W and may be assumed constant. For a slip of 2.8 % determine (a) The line current and the power factor (b) The shaft torque and output horsepower (c) The efficiency

Homework Equations

The Attempt at a Solution


To get the line current, I need the equivalent impedance. But how do I get Rc (core resistance) ?, Is their a way to get it or is it just neglected because it is very large ?
 
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TheRedDevil18 said:
the core losses amount to 262 W and may be assumed constant.
You're wondering how to involve this detail in your calculations?
 
NascentOxygen said:
You're wondering how to involve this detail in your calculations?

For question a), it says determine the line current, so IL = Vphase/Z, but they haven't given Rc. They also said that the core losses and rotational losses amount to 262W
 
Can you express these fixed losses as their equivalent in line current and then add that in after you have done the other calculations?

N.B., I'm not sure this is the accepted approach, but it seems a valid approximation.
 
NascentOxygen said:
Can you express these fixed losses as their equivalent in line current and then add that in after you have done the other calculations?

N.B., I'm not sure this is the accepted approach, but it seems a valid approximation.

Not sure how to do that, I have this equation

IL = Vphase/Zeq

Where Zeq would be the equivalent impedance of the circuit, but then I would have to neglect Rc
 
TheRedDevil18 said:
Not sure how to do that, I have this equation

IL = Vphase/Zeq

Where Zeq would be the equivalent impedance of the circuit, but then I would have to neglect Rc
Once you have taken account of Rc losses separately, you can then neglect Rc in the equivalent circuit. Which equivalent circuit are you using?
 

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