- #1
nagyn
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- TL;DR Summary
- I am trying to make an induction stovetop using some magnet wire. I understand how induction stovetops work but am less confident on the math I've done to design one. Can you double-check that I'm approaching this correctly?
I've been told an effective induction stovetop needs to deliver about 1000W of power. I have magnet wire that can tolerate at most about 0.2A of current, and was planning on using a 60Hz wall outlet as my source (obviously I'll need to bring down the outlet current quite a bit).
So the energy stored in an inductor is given by:
E = 0.5*I2*L
Which I assume would be roughly the same energy transferred to the pot when on the stove. So the power delivered would be
P = E / t = E*(60 Hz)
Then substituting P = 1000W and I = 0.2A I get that L = 1.2mH.
Then given that L = μ0*N2*A / ι , I find that I need a ratio close to
N2*A / ι = 952
So if I had a coil with 10 turns, the area would need to be about 10 times the length to deliver the power I need.
Am I doing this right? Did I mess up anywhere in my understanding?
So the energy stored in an inductor is given by:
E = 0.5*I2*L
Which I assume would be roughly the same energy transferred to the pot when on the stove. So the power delivered would be
P = E / t = E*(60 Hz)
Then substituting P = 1000W and I = 0.2A I get that L = 1.2mH.
Then given that L = μ0*N2*A / ι , I find that I need a ratio close to
N2*A / ι = 952
So if I had a coil with 10 turns, the area would need to be about 10 times the length to deliver the power I need.
Am I doing this right? Did I mess up anywhere in my understanding?
Sorry, I don't know of anyplace that has 5000 Volts at their wall outlets.