Inductor and Capacitor at different frequencies

AI Thread Summary
When an inductor and capacitor are connected to the same AC voltage, the current behavior varies with frequency. The current through a capacitor increases with frequency, while the current through an inductor decreases with frequency. At low frequencies, the inductor's current can be lower than the capacitor's, but at high frequencies, the inductor's current can exceed that of the capacitor. The relationship between these currents can be analyzed using their respective formulas, revealing that the inequality IL > IC can be satisfied under certain conditions. Thus, the statement about the inductor always having a higher current than the capacitor is not universally true across all frequencies.
tomrja
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Homework Statement



When a particular inductor and capacitor are connected across the same AC voltage, the current in the inductor is higher than in the capacitor. Is this true for all frequencies?

Homework Equations



Current through a capacitor Ip=(Vp)(2pi)(f)(C)

Current through an inductor Ip=(Vp)/((2pi)(f)(L))

The Attempt at a Solution



I know that the formula for the current in a capacitor is Ip=(Vp)(2pi)(f)(C) and the current through an inductor is Ip=(Vp)/((2pi)(f)(L)). So, to me it looks like the current through the capacitor would be larger than the current through the inductor at a given frequency, but the question itself states otherwise.

Thank you for your help!
 
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tomrja said:
So, to me it looks like the current through the capacitor would be larger than the current through the inductor at a given frequency, but the question itself states otherwise.


Not true at all, set up the ratio of current through the inductor (IL) to current through the capacitor IC and ask yourself what sort of inequality must be satisfied for IL>IC. You'll see it's quite reasonable. Remember, common capacitors and inductors have very tiny values in SI units. Next, ask yourself if there could be a frequency such that IL<IC
 
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