How Does Inelastic Collision Facilitate Ionization and Excitation in Plasma?

VulpineNinja
Messages
3
Reaction score
0
1. Explain why it is important for inelastic equation to occur in a plasma in order for process such as ionization and excitation to happen.

2. 1/2(m1u1^2) = 1/2(m1)(v1^2 + u1^2 sin^2(theta)) + 1/2(m2v2^2) + (delta)U3. According to the inelastic equation above, in order for ionization and excitation to happen there should be an energy loss. And it is possible for atom to get excited or release electrons if another electron collides with the atom in inelastic equation. Which means that m1 must be smaller than m2

Sorry I don't have any software to write the equation clearly.
Anyways, I'm not sure how am I supposed to answer the question (should I explain the process based on the equation to prove my statement?), or that if my answer is accurate enough. Like, how do I relate with the loss of energy, (delta)U?
And furthermore, what makes inelastic collision (in plasma) more important than elastic?
 
Last edited:
Physics news on Phys.org
I guess ionization and excitation require some energy in order to happen and that energy is the loss in the kinetic energy (delta)U.
 
Hello everyone, I’m considering a point charge q that oscillates harmonically about the origin along the z-axis, e.g. $$z_{q}(t)= A\sin(wt)$$ In a strongly simplified / quasi-instantaneous approximation I ignore retardation and take the electric field at the position ##r=(x,y,z)## simply to be the “Coulomb field at the charge’s instantaneous position”: $$E(r,t)=\frac{q}{4\pi\varepsilon_{0}}\frac{r-r_{q}(t)}{||r-r_{q}(t)||^{3}}$$ with $$r_{q}(t)=(0,0,z_{q}(t))$$ (I’m aware this isn’t...
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
Back
Top