Inelastic Collision Problem. Help

AI Thread Summary
In an inelastic collision problem, a moving cart of mass 1.2 kg at 3 m/s collides with a stationary block of wood weighing 0.8 kg. Since the collision is inelastic, momentum is conserved while kinetic energy is not. The total momentum before the collision can be calculated using the masses and velocities of both objects. By applying the principle of momentum conservation, the velocity of the combined mass after the collision can be determined. This approach effectively finds the velocity of the composite body post-collision.
blue_bee29
Messages
4
Reaction score
0

Homework Statement



A cart of mass 1.2 kg that is moving to the right qt 3m/s collides on a block of wood of mass 0.8 kg that is lying at rest on top of a frictionless table. if the collision is inelastic, find the velocity of the composite body.

Homework Equations





The Attempt at a Solution


 
Physics news on Phys.org
Well..

you know that the collision is inelastic, so kinetic energy will not be conserved, but momentum will be. You know the masses and the velocities before the collision as well as their velocities, and you can safely assume that mass is conserved, you can use momentum conservation to find the velocity of the composite body.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'

Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'

Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is（Figure 2）： F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Perfectly inelastic collision of two moving and rotating disks
Replies
9
Views
2K
Potential Energy - 2D inelastic collision - ballistic pendulum
Replies
10
Views
2K
Inelastic collision, determine ratio KEf/KEi
Replies
3
Views
3K
Can total KE ever increase for inelastic collisions?
Replies
5
Views
2K
Why is momentum conservation always true in a collision?
Replies
4
Views
2K
Inelastic Collision: Finding Initial Angle
Replies
22
Views
4K
Elastic and inelastic collisions
Replies
4
Views
3K
Question regarding inelastic/elastic collision.
Replies
2
Views
2K
Inelastic collision with an inclined plane
Replies
7
Views
4K
Inelastic Collision Problem. Help
Replies
1
Views
2K

Hot Threads

Recent Insights

Back
Top