Inelastic collisions between two blocks

AI Thread Summary
In an inelastic collision problem, a 2.0 kg block moving at 1.0 m/s is struck by a second block moving at 4.0 m/s, resulting in both blocks moving together at 2.0 m/s. The conservation of momentum equation is applied to find the mass of the second block. After setting up the equation and simplifying, it is determined that the mass of the second block is 1 kg. The discussion emphasizes the importance of correctly applying the conservation of momentum principle. The participants express satisfaction with the solution process and the learning experience.
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Homework Statement



A 2.0 kg block slides along a frictionless surface at 1.0 m/s. A second block, sliding at a faster 4.0 m/s, collides with the first from behind and sticks to it. The final velocity of the combined blocks is 2.0 m/s. What is the mass of the second block?

Homework Equations



law of conservation of momentum...

m1u1 + m2u2 = m1v1 + m2v2

The Attempt at a Solution



(2 kg * 1 m/s ) + (m2 * 4 m/s) = (2kg + m2) 2.0 m/s

2 J + (4 m/s m2) = 4 J + (2.0 m/s m2)

4 m/s m2 = 2 J + (2.0 m/s m2)

now I'm lost...
 
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Just finish your algebra

by the way kgm/sec is not joule, it's just kg m/sec, which is the same as N sec

so you have the equivalent of

4m = 2 + 2m

subtracting 2m from both sides
2m = 2

m = 1kg
 
Thanks netgypsy... now i feel like a true student. haha
 
Good job!
 
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