Understanding and Solving Inequalities Involving Square Roots and Fractions

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The discussion revolves around solving the inequality √(x+2) + 1/x+2 > 0, with participants clarifying the correct interpretation of the expression. There is confusion regarding whether the term is √(x+2) + 1/x + 2 or √(x+2) + 1/(x+2). Participants emphasize the importance of clear notation to avoid ambiguity and suggest rearranging the inequality into a fraction format for easier analysis. They recommend determining the domain of x and using a sign chart to evaluate the positivity or negativity of the components involved. The conversation highlights the complexity of inequalities involving square roots and fractions, underscoring the need for precise mathematical expression.
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Can you guys help me solve this inequality

√(x+2) + 1/x+2 >0

thanks
 
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Is that

\sqrt{x+2} + \frac{1}{x} + 2 > 0
or
\sqrt{x+2} + \frac{1}{x+2} > 0

?

You must be careful with your notation to ensure that there isn't ambiguity!

--J
 
Hi,
Try to arrange it to:
\frac{A}{B} <= 0
Or
\frac{A}{B} >= 0
Where A = a_{1} \times a_{2} \times a_{3} \times ... \times a_{n}
and B = b_{1} \times b_{2} \times b_{3} \times ... \times b_{k}
Then just simply solve the inequation by drawing a chart to see if each element is positive or negative or zero. And finally, see if \frac{A}{B} is positive or negative or zero in each case.
Hope this help,
Viet Dao,
 
o..icic..thx...
do you have to do the "cases" for it?
 
You may want to begin by stating clearly the domain of the "x"...And then look for those "x" which would satisfy your inequation.

Daniel.
 
If the question is designed as "equal or bigger",it is more tricky.
 
I still want to know what √(x+2) + 1/x+2 >0 is.

How we decided yet?

Is it:

\sqrt{\frac{(x + 2) + 1}{x + 2}} > 0

Is it:

\sqrt{(x + 2) + \frac{1}{x + 2}} > 0

or something else?

The Bob (2004 ©)
 
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