Inertia Tensor as a Transformation

AI Thread Summary
The discussion focuses on the relationship between angular velocity and angular momentum in rigid bodies, expressed as Iω = L. It explores the transformation of the inertia tensor using a reference frame at the center of mass, represented as I = R I₀ Rᵀ, where I₀ is the diagonalized inertia tensor. The transformation involves rotating and scaling angular velocity components, leading to a complex interplay of transformations. The author notes significant freedom in designing the inertia tensor and rotation matrix, although a key restriction is that the inner product of angular velocity and angular momentum must remain positive. Overall, the exploration highlights the intricate nature of inertia tensor transformations in rigid body dynamics.
uliuli
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Hi everyone,

I was thinking about the relationship between angular velocity and angular momentum for a rigid body: I \omega = L. In particular, I'm trying to gain a little bit of intuition as to what transformations I can perform on \omega.

Let's use a reference frame at the center of mass of the body. We can rewrite the inertia tensor as: I = R I_0 R^T, where I_0 is the diagonalized inertia tensor and R rotates the coordinate system from a principle-axes-aligned frame to the current frame. When I now apply I to \omega, I am equivalently rotating \omega by some arbitrary rotation, scaling each component by a positive (and in general, different for each component) number, and rotating by the inverse of the first rotation. In general, what does this concatenation of transformations give me?

Thanks!
 
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To reply to my own thread :):

The more I think about this, the less I think one can say about the family of transforms that I can perform. I can 'design' I_0 to be arbitrarily close to a projection onto a cartesian axis, I can make R any rotation I want... there is a lot of freedom.

About the only concrete restriction on the transform I've come up with is that \omega and L have a positive inner product: \omega^T L = \omega^T R I_0 R^T \omega = (R^T \omega)^T I_0 (R^T \omega) = \tilde{\omega}^T I_0 \tilde{\omega} > 0 due to the positive definiteness of I_0.

Ohh well!
 
Hi there, im studying nanoscience at the university in Basel. Today I looked at the topic of intertial and non-inertial reference frames and the existence of fictitious forces. I understand that you call forces real in physics if they appear in interplay. Meaning that a force is real when there is the "actio" partner to the "reactio" partner. If this condition is not satisfied the force is not real. I also understand that if you specifically look at non-inertial reference frames you can...
This has been discussed many times on PF, and will likely come up again, so the video might come handy. Previous threads: https://www.physicsforums.com/threads/is-a-treadmill-incline-just-a-marketing-gimmick.937725/ https://www.physicsforums.com/threads/work-done-running-on-an-inclined-treadmill.927825/ https://www.physicsforums.com/threads/how-do-we-calculate-the-energy-we-used-to-do-something.1052162/
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