Inertia tensor for multibody system(Robot)

AI Thread Summary
The discussion focuses on calculating the inertia tensor for a legged robot with six legs, each having three degrees of freedom, resulting in a total of 19 moving parts. The center of mass for the entire robot can be determined using a mass-weighted sum of the individual parts. The challenge lies in deriving the overall inertia tensor from the tensors of the individual components, which requires the application of the parallel axis theorem. The procedure involves transforming the center of mass coordinates through the robot's links and adjusting the inertia tensors accordingly. The participants confirm that the outlined method for calculating the overall inertia tensor is fundamentally correct, though there are some uncertainties regarding the specific formula used.
Sigurdv
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Hi,
I'm trying to make a simulation of a legged robot. The Robot consists of a body, with 6 legs attached, all with three DOF. This entails that i have a total of 19(18 from the legs + 1 from the body) moving parts. To be able to make a simulation, i need the centre of mass and the inertia tensor of the entire robot.
I have the centre of mass and tensors for the individual parts(+all forces(impact+friction), angles, angular velocities and accelerations).

The centre of mass of the entire robot is quite easy to find, using a mass weighted sum of the centre of masses, but I'm having trouble finding a way to derive the inertia tensor of the entire system from the tensors of the smaller parts.

Any help would be greatly appreciated

Sigurd
 
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Welcome to PF!

Hi Sigurd! Welcome to PF! :smile:

The total inertia tensor Itotal about the overall c.o.m. is the sum of the inertia tensors In of each part, all about the overall c.o.m.

so you need the parallel axis theorem, to convert the principal moments of inertia of each part about its own c.o.m. into moments of inertia about the overall c.o.m. (and then you have the tricky part of converting them all to the same x,y,z axes, since I assume the principal axes of different parts won't be parallel :redface:)
 
Hi again, thanks for the big welcome:smile:, and fast reply. I think i understand the procedure you explained to me, but just to be shure that I'm on the right track.
Example:
The robot legs consist of three links, each with a coordinate frame attached(frame 1, 2 and 3). If i want to find the contribution of the last link(link 3) of one of the legs to the overall inertia tensor, i do the following:

First i find the centre of mass of the last link, in coordinate frame 3:
<br /> ^{3}COM=[x_3\ y_3\ z_3\ 1]^T<br />
And then the inertia tensor(aligned with coordinate frame 3)
<br /> ^{3}\mathbf{I}<br />

I then move the coordinates of the COM through the links, to come to the centre of the robot(Where i want derive the overall inertia tensor)

<br /> ^{c}COM=[x_c\ y_c\ z_c\ 1]^T=_1^cT\cdot_2^1T \cdot _3^2T \cdot [x_3\ y_3\ z_3\ 1]^T<br />
Where T is a transformation matrix derived by using the denavit hartenberg notation(Just a normal translation+rotation matrix).
Now that i have the COM position in the central coordinate frame, and then by the parallel axis theorem i get the new tensor.
<br /> ^{c}\mathbf{I} =\ ^{3}\mathbf{I} + m(r^2\mathbf{1} - \mathbf{r}\mathbf{r}^T)<br />

I then need to do this for all centre of masses, add them together and finally i have the overall inertia tensor of the robot.

Is this procedure correct or am doing something completely wrong
 
Sigurdv said:
… I then need to do this for all centre of masses, add them together and finally i have the overall inertia tensor of the robot.

Hi Sigurd! :wink:

Yes, that looks ok. :smile:

(though I can't remember whether your (r2I - rrT) formula is correct … I've never had to combine tensors with different orientations, so I've never looked it up!)
 
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