- #1

- 177

- 1

What?

[tex]W = \frac{\epsilon_{0}}{2} \int E^2 d \tau = \frac{\epsilon_{0}}{2 \left( 4 \pi \epsilon_{0} \right)^{2}} \int \frac{q^{2}}{r^{4}} r^{2} sin \theta dr d \theta d \phi = \frac{q^{2}}{8 \pi \epsilon_{0}} \int_{0}^{\infty} \frac{1}{r^{2}} dr = \infty [/tex]

Griffith explains this infinite energy coming from the charge being required to assemble itself. What does this mean? Surely tearing apart an electron would not solve all of humanities energy problems. Or is the problem that an actual unit of charge is discrete, whereas the equation treats it as a continuous charge distribution? I'm not sure I understand.

[tex]W = \frac{\epsilon_{0}}{2} \int E^2 d \tau = \frac{\epsilon_{0}}{2 \left( 4 \pi \epsilon_{0} \right)^{2}} \int \frac{q^{2}}{r^{4}} r^{2} sin \theta dr d \theta d \phi = \frac{q^{2}}{8 \pi \epsilon_{0}} \int_{0}^{\infty} \frac{1}{r^{2}} dr = \infty [/tex]

Griffith explains this infinite energy coming from the charge being required to assemble itself. What does this mean? Surely tearing apart an electron would not solve all of humanities energy problems. Or is the problem that an actual unit of charge is discrete, whereas the equation treats it as a continuous charge distribution? I'm not sure I understand.

Last edited: