Infinite series Geometric series

[Pual Black]

Homework Statement

hello
i have a question to this solved problem in the book

" Mathematical Methods for Physics and Engineering Third Edition K. F. RILEY, M. P. HOBSON and S.J. BENCE "
page 118

Consider a ball that drops from a height of 27 m and on each bounce retains only a third
of its kinetic energy; thus after one bounce it will return to a height of 9 m, after two
bounces to 3 m, and so on. Find the total distance traveled between the first bounce and
the Mth bounce.

Homework Equations

i have to use this equation
S_M=a \frac{1-r^M}{1-r}
so a=9 because he wants the distance from the first bounce
if he just said " find the total distance " i have to put a=27 right?
the common ration is d=\frac{1}{3}
the ball goes up and down so i have to multiply the sum by 2 to get the total distance
now
S_M=2*9 [\frac{1-(\frac{1}{3})^{M-1}}{1-\frac{1}{3}}]
S_M=27 [1-(\frac{1}{3})^{M-1}]

i only don't understand why he put (M-1) not just (M)

The Attempt at a Solution

i thought maybe if I just put M then the ball will bounce for last time and be hanging in the air.
but if i put M-1 then the ball will hit the ground and stop
right?

 

[andrewkirk]

How many return trips from ground to an apex up in the air are there between the 1st bounce and the M-th bounce?

 

[Pual Black]

How many return trips from ground to an apex up in the air are there between the 1st bounce and the M-th bounce?

i think until the factor (\frac{1}{3})^{M-1} approaches zero
so I am not sure but may i put this factor to zero
(\frac{1}{3})^{M-1}=0
then i can calculate M
right?

 

[Pual Black]

How many return trips from ground to an apex up in the air are there between the 1st bounce and the M-th bounce?

i think until the factor (\frac{1}{3})^{M-1} approaches zero
so I am not sure but may i put this factor to zero
(\frac{1}{3})^{M-1}=0
then i can calculate M
right?

 

[Ray Vickson]

i think until the factor (\frac{1}{3})^{M-1} approaches zero
so I am not sure but may i put this factor to zero
(\frac{1}{3})^{M-1}=0
then i can calculate M
right?

That equation is very easy to solve: its solution is $M = + \infty$.

However, that equation has absolutely nothing to do with the original question. I suggest you re-read the problem.

 

[vela]

The Attempt at a Solution

i thought maybe if I just put M then the ball will bounce for last time and be hanging in the air.
but if i put M-1 then the ball will hit the ground and stop
right?

Forget about the formula for a minute, and try working out what distance the ball travels between the first bounce and the second (M=2) bounce, the first bounce and the third (M=3) bounce, and so on. Once you see the pattern, write down the appropriate series for the Mth bounce, and then apply the sum formula to that series.

You should see your guesses about M vs. M-1 don't really make sense.

 

[Pual Black]

Forget about the formula for a minute, and try working out what distance the ball travels between the first bounce and the second (M=2) bounce, the first bounce and the third (M=3) bounce, and so on. Once you see the pattern, write down the appropriate series for the Mth bounce, and then apply the sum formula to that series.

You should see your guesses about M vs. M-1 don't really make sense.

the series is not difficult
S_M=a+ar^2+ar^3+...ar^M
substituting my information
S_M=2[9+9\frac{1}{3}+9(\frac{1}{3})^2+...+9(\frac{1}{3})^M]

if i want the distance between the first bounce and the second bounce i have to calculate the first 2 terms of the series.

 

[vela]

If i want the distance between the first bounce and the second bounce i have to calculate the first 2 terms of the series.

Really? After the first bounce, it reaches a height of 9 m, so the total distance is travels until the second bounce is 18 m. That's not equal to the sum of the first two terms of your series.

 

[Pual Black]

Hey i get it. The distance traveled between the first bounce and the second bounce is just the first term.

The distance traveled between the first bounce and the third bounce is the first two terms.

Therefore the distance between the first bounce and the Mth bounce is adding all terms until (Mth-1)
Right?

But if the question just said ( find the total distance ?)
I think i have to add 27m to the final sum and replace (M-1) by (M)