What is the Convergence of the Infinite Sum with k^(1/k)?

In summary, the problem is to show that the series \sum_{k=0}^{\infty} \sqrt[k]k-1 converges. To do this, we can use the ratio, radix theorems, and comparison with other sums. One approach is to consider the general term a_k = \sqrt[k]{k} - 1 and prove that \lim_{k \rightarrow \infty}{a_k} = 0. Then, we can manipulate the expression to get a_{k+1} in terms of a_{k} and use the asymptotic comparison test to find the comparison general term b_n. The series \sum_{n = 1}^{\infty}{b
  • #1
Quinzio
558
1

Homework Statement



Show that
[tex]\sum_{k=0}^{\infty} \sqrt[k]k-1 [/tex]

converges.

Homework Equations



Ratio, radix theorems, comparison with other sums...


The Attempt at a Solution



No idea whatsoever.
Where does one begin in this case ? With other cases I'm quite confident.
 
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  • #2
Hint:
Let the general term be denoted by:
[tex]
a_k = \sqrt[k]{k} - 1
[/tex]
Do you know how to prove that [itex]\lim_{k \rightarrow \infty}{a_k} = 0[/itex]?
Then, we have:
[tex]
k = (1 + a_k)^{k}
[/tex]
Taking the same equality for [itex]k + 1[/itex], and subtracting this one, you ought to get:
[tex]
1 = (1 + a_{k + 1})^{k + 1} - (1 + a_k)^{k}
[/tex]
Solve this equation for [itex]a_{k + 1}[/itex]. What do you get?

Because as [itex]k \rightarrow \infty[/itex], [itex]a_k[/itex] is an infinitesimal quantity, you may expand your expression for [itex]a_{k + 1}[/itex] in powers of [itex]a_{k}[/itex] up to the first non-vanishing order. What do you get?

The solution for this asymptotic recursion relation would give you a comparison general term [itex]b_n[/itex], and the series [itex]\sum_{n = 1}^{\infty}{b_n}[/itex] is pretty easy to test for convergence. Then, you may use the [STRIKE]Ratio comparison test[/STRIKE].

EDIT:
Use the Asymptotic comparison test mentioned here instead.
 
Last edited:
  • #3
I don't quite follow you.

I sort of need simpler methods, thanks anyway.
 
  • #4
Yep, asymptotic comparison seems a good way.
 

1. What is an infinite sum with k^(1/k)?

An infinite sum with k^(1/k) is a mathematical series in which the terms are progressively raised to the power of 1/k, where k is the index of the term. This type of series is known as a "root series" and is used to model certain types of growth or decay.

2. How is an infinite sum with k^(1/k) calculated?

An infinite sum with k^(1/k) can be calculated using various methods, such as the ratio test or the comparison test. It can also be approximated using numerical methods, such as the Euler-Maclaurin formula.

3. What are the applications of an infinite sum with k^(1/k)?

Infinite sums with k^(1/k) have various applications in mathematics, physics, and engineering. They are used to model population growth, radioactive decay, and other natural phenomena. They also have connections to other areas of mathematics, such as the Riemann zeta function.

4. Can an infinite sum with k^(1/k) converge to a finite value?

Yes, an infinite sum with k^(1/k) can converge to a finite value, depending on the value of k. For example, the series 1 + (1/2)^(1/2) + (1/3)^(1/3) + (1/4)^(1/4) + ... converges to approximately 1.29128.

5. Are there any special properties of an infinite sum with k^(1/k)?

Yes, infinite sums with k^(1/k) have some interesting properties. For example, they can be used to prove the irrationality of certain numbers, such as e and π. They also have connections to other mathematical concepts, such as the gamma function and the Lambert W function.

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