Initial Values in circuit problems

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SUMMARY

The discussion centers on the confusion surrounding initial conditions in circuit problems, specifically regarding an initial current of 8mA when a switch is open. Participants conclude that this scenario is nonsensical unless another switch was previously closed, allowing current to flow from an external voltage source before the switch was opened. The final steady-state current is confirmed to be 4.2mA, indicating that the initial current must originate from an unseen source. This highlights the importance of accurately representing circuit conditions in problem statements.

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exis
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While going through some textbook problems I encountered several circuits that had initial conditions like the one attached where there's an initial current of 8mA when the switch is open. What's the source of that current? how can there be a current if the circuit is open?

http://img710.imageshack.us/img710/7132/73399543.jpg

Thanks
 
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exis said:
While going through some textbook problems I encountered several circuits that had initial conditions like the one attached where there's an initial current of 8mA when the switch is open. What's the source of that current? how can there be a current if the circuit is open?

http://img710.imageshack.us/img710/7132/73399543.jpg

Thanks

That is definitely nonsensical as drawin. The only way you could establish that initial condition for time t = 0- would be if there were another switch that was closed for a time from some other voltage source, and opened just as the other switch were closed.

BTW, the current they mention of 8mA is larger than the final value of the current at t = infinity, right? So for sure that current had to be established by something else not shown in the figure, and presumably disconnected at t = 0 simultaneous with the closing of the switch shown. Weird.
 
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berkeman said:
BTW, the current they mention of 8mA is larger than the final value of the current at t = infinity, right?

Yes it is.. the final current is 4.2mA. But just like you said, it certainly makes more sense that the initial 8mA is a result of some external source that is not being shown.Thanks a lot for replying berkeman :)
 

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