Initial Velocity of 1.52 m High Jump Record

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SUMMARY

The initial velocity required for a high jump of 1.52 meters from a standing position can be calculated using the principles of physics. The key factors include the acceleration due to gravity, which is 9.8 m/s², and the fact that the jumper's velocity is zero at the peak of the jump. By applying the kinematic equations, one can derive the necessary initial velocity to achieve this height. The solution involves understanding the relationship between height, acceleration, and velocity.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of gravitational acceleration (9.8 m/s²)
  • Familiarity with the concept of peak velocity in projectile motion
  • Basic algebra skills for solving equations
NEXT STEPS
  • Study the kinematic equations for projectile motion
  • Learn how to derive initial velocity from height using physics principles
  • Explore examples of vertical motion problems in physics
  • Investigate the effects of different initial velocities on jump height
USEFUL FOR

Students studying physics, educators teaching mechanics, and athletes interested in understanding the physics behind high jump performance.

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Homework Statement



Assuming the best high jump record from a standing position in a school was 1.52 m, what initial velocity was needed for this jump? neglect any sideways motion.

Homework Equations



velocity equation


The Attempt at a Solution



I don't really understand how to do the question? Is there a knowledge part involved that I can't figure out? There is only one given data?
 
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That is not true. Think about the situation more thoroughly. You know that his acceleration is 9.8m/s downwards. You also know that his 1.52 metres is achieved at the peak of his jump, at which time his velocity will be 0. So now you 3 pieces of information.
 
dacruick said:
That is not true. Think about the situation more thoroughly. You know that his acceleration is 9.8m/s downwards. You also know that his 1.52 metres is achieved at the peak of his jump, at which time his velocity will be 0. So now you 3 pieces of information.

Thanks I got the answer :D & How to do it :D
 

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