Intake Temperature for a 40.2% Efficient Carnot Engine

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SUMMARY

The intake temperature for a Carnot engine with an exhaust temperature of 401°C and an efficiency of 40.2% is calculated to be approximately 130.052°C. The efficiency formula used is e = 1 - Tc/Th, where Tc is the intake temperature in Kelvin and Th is the exhaust temperature in Kelvin (674 K). The initial miscalculation arose from incorrectly attempting to derive Tc from Th instead of the intended approach. The correct method confirms that Tc is derived from the known Th value.

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  • Understanding of Carnot engine principles
  • Familiarity with thermodynamic efficiency calculations
  • Knowledge of temperature conversion between Celsius and Kelvin
  • Proficiency in algebraic manipulation of equations
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  • Learn about the derivation and application of the efficiency formula e = 1 - Tc/Th
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Students studying thermodynamics, engineers working with heat engines, and anyone interested in understanding the principles of thermal efficiency in Carnot engines.

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Homework Statement


The exhaust temperature of a Carnot heat engine is 401◦ C.
What is the intake temperature if the efficiency of the engine is 40.2 %?
Answer in units of ◦ C.


Homework Equations



e = 1 - Tc/Th (all in Kelvin)


The Attempt at a Solution


0.402 = 1 - Tc/ (401+273) = 1 - Tc/674
Tc = 0.598 * 674 = 403.052
Tc in C = 403.052-273 = 130.052

But somehow this answer seems to be wrong on the quest. This is my last problem ..please help? What am I doing wrong? Am I missing something?
 
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You were given Tc to get Th, not the other way around like you did.
 
Thanks .. that worked.
 

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