- #1
James889
- 192
- 1
Hai,
I have the following Integral i can't get right:
[tex]\int_{-8}^8\frac{(6e^{4x}-2)^2}{e^{4x}}[/tex]
After i squared the bracket i end up with[tex]~~\frac{36e^{8x}-24e^{8x}+4}{e^{4x}}[/tex]
So, after dividing thru by [tex]e^{4x}[/tex] i have:
[tex]36e^{4x}-24e^{4x}+\frac{4}{e^{4x}}[/tex]
Integrating gives:
[tex]9e^{4x} - 6e^{4x} +4~ln(e^{4x})[/tex]
I must be doing something wrong because i end up with the wrong answer =/
But what?
I have the following Integral i can't get right:
[tex]\int_{-8}^8\frac{(6e^{4x}-2)^2}{e^{4x}}[/tex]
After i squared the bracket i end up with[tex]~~\frac{36e^{8x}-24e^{8x}+4}{e^{4x}}[/tex]
So, after dividing thru by [tex]e^{4x}[/tex] i have:
[tex]36e^{4x}-24e^{4x}+\frac{4}{e^{4x}}[/tex]
Integrating gives:
[tex]9e^{4x} - 6e^{4x} +4~ln(e^{4x})[/tex]
I must be doing something wrong because i end up with the wrong answer =/
But what?