Integral evaluation.

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49
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Question,
Evaluate:
[tex]\sum_{k=1}^{\ 6}\ f(xk)[/tex]
where
[tex]\ xk\ = \ k/2[/tex]
and
[tex]\ f(x)=sin\pi\ x[/tex]

OK,
does this mean that that I should form a RiemannSum with;
[tex]sin\pi\ (k/2)* delt(k/2)= \sum_{k=1}^{\ 6}f(k/2)delt(k/2) [/tex]

Im confused.
 
Last edited:

Answers and Replies

92
0
I cannot see your problem, it is a trivial substitution

[tex]\sum_{k=1}^{\ 6}\ f(xk) = \sum_{k=1}^{\ 6}\ \sin(k\frac{\pi}{2})=1[/tex]
 
49
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Thankyou,
sometimes I get muddled when working with calculus, and often percieve things as being a lot harder than they are.

Thanks again.
 
92
0
Ok, quite an usual occurrence!
 

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