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Integral evaluation.

  1. Aug 9, 2005 #1
    [tex]\sum_{k=1}^{\ 6}\ f(xk)[/tex]
    [tex]\ xk\ = \ k/2[/tex]
    [tex]\ f(x)=sin\pi\ x[/tex]

    does this mean that that I should form a RiemannSum with;
    [tex]sin\pi\ (k/2)* delt(k/2)= \sum_{k=1}^{\ 6}f(k/2)delt(k/2) [/tex]

    Im confused.
    Last edited: Aug 9, 2005
  2. jcsd
  3. Aug 9, 2005 #2
    I cannot see your problem, it is a trivial substitution

    [tex]\sum_{k=1}^{\ 6}\ f(xk) = \sum_{k=1}^{\ 6}\ \sin(k\frac{\pi}{2})=1[/tex]
  4. Aug 10, 2005 #3
    sometimes I get muddled when working with calculus, and often percieve things as being a lot harder than they are.

    Thanks again.
  5. Aug 10, 2005 #4
    Ok, quite an usual occurrence!
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