How to Solve Complex Integrals in Lagrangian Mechanics?

Kuryakin
Messages
10
Reaction score
0

Homework Statement



Trying to solve a Lagrangian, got down this integral. Unfortunately the zeroth-solution isn't good enough since the constant k is close to 1 for our experimental set-up.

<br /> <br /> <br /> \int_{0}^{x}dx(\frac{xsin(x)}{1+kcos^2(x)}})^\frac{1}{2}<br /> <br /> Any hints? I'm not sure where to get started.
 
Physics news on Phys.org
It's a typical elliptic integral. It can be solved only approximately.
 
Thanks. I'll have a go at the taylor expansions later.
 
Had an attempt at the Taylor series and it looked like it was just going to make it more complex. I've plotted it in excel and get a nice semi-ellipse then I'll just use simpsons rule to solve for the area.
 
\int_{0}^{x}\frac{xsin(x)dx}{1-kcos^2(x)}}<br /> <br />

Looks a little more friendly. Is this still only solvable by approximate methods?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top