Integral Homework: √(3 - x^2) 0 to 3/2

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Homework Statement



∫(√(3 - x^2), x, 0, 3/2)

the integral of √(3 - x^2) with 0 extr inf and 3/2 extr sup

Homework Equations





The Attempt at a Solution



i have to use the subsitution rule, i thought x= (1/√3) sin t
any other hint?

thanx
 
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"i thought x= (1/√3) sin t"

Just thinking about it won't get you very far!

Try it. If it works, you are done. If it doesn't work, then think again.
 
Hi ddr,

The substitution should be x= √3 sin t instead. Then, dx = √3 cos t dt. Remember to change the limits for the trigo substitution. Use your trigo identities to evaluate the final integral.

Hope that helps.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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