Integral involving product of derivatives of Legendre polynomials

Click For Summary

SUMMARY

The integral \(\int_{-1}^{1} (1-x^2) P_{n}^{'} P_m^{'} dx\) can be evaluated using integration by parts and the properties of Legendre polynomials. The key facts include the recurrence relation \(\left((1-x^2)P_n^\prime \right)^\prime=-n(n+1)P_n\) and the orthogonality condition \(\int_{-1}^1 P_m P_n \text{ dx}=\dfrac{2}{2n+1} \delta_{mn}\). Utilizing these relationships allows for a systematic approach to solving the integral effectively.

PREREQUISITES

  • Understanding of Legendre polynomials and their properties
  • Familiarity with integration by parts technique
  • Knowledge of recurrence relations for derivatives of Legendre polynomials
  • Basic concepts of orthogonality in polynomial functions

NEXT STEPS

  • Study the derivation and applications of Legendre polynomial recurrence relations
  • Explore advanced integration techniques involving special functions
  • Learn about the properties of orthogonal polynomials in mathematical physics
  • Investigate the use of Legendre polynomials in solving differential equations

USEFUL FOR

Mathematicians, physicists, and students studying mathematical methods in physics, particularly those focusing on special functions and orthogonal polynomials.

hanson
Messages
312
Reaction score
0
Anyone how to evaluate this integral?

[itex]\int_{-1}^{1} (1-x^2) P_{n}^{'} P_m^{'} dx[/itex], where the primes represent derivative with respect to [itex]x[/itex]?

I tried using different recurrence relations for derivatives of the Legendre polynomial, but it didn't get me anywhere...
 
Physics news on Phys.org
Use the facts

[tex]\left((1-x^2)P_n^\prime \right)^\prime=-n(n+1)P_n[/tex]

and

[tex]\int_{-1}^1 P_m P_n \text{ dx}=\dfrac{2}{2n+1} \delta_{mn}[/tex]

to integrate by parts

or just use

[tex]P_n=\frac{1}{(2n)!} \dfrac{d^n}{dx^n} (x^2-1)^n[/tex]
 
Last edited:
Thank you very much!
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 6 ·
Replies
6
Views
6K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
6K