- #1
UrbanXrisis
- 1,196
- 1
say a ball falling through shampoo had a drag force of F=6.5v
the differential equation for the objects motion is:
mdv/dt=6.5v
to solve it, I get all of the v value on one side and integrate them:
dv/v=(6.5/m)(dt)
integral[dv/v]=integral[(6.5/m)(dt)]
I know that integral[(6.5/m)(dt)] becomes 6.5t/m+c, but what will happen to the dv/v?
the differential equation for the objects motion is:
mdv/dt=6.5v
to solve it, I get all of the v value on one side and integrate them:
dv/v=(6.5/m)(dt)
integral[dv/v]=integral[(6.5/m)(dt)]
I know that integral[(6.5/m)(dt)] becomes 6.5t/m+c, but what will happen to the dv/v?