Integral representation of Euler constan

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SUMMARY

The integral representation of the Euler-Mascheroni constant is clarified through the transformation of the first integral from exp(-u)lnu to (1-exp(-u))lnu. This transformation occurs because the first integral is evaluated over the interval from 1 to 0, while the second integral, exp(-u)lnu, is evaluated from 1 to infinity. Understanding this distinction is crucial for grasping the properties of the Euler-Mascheroni constant.

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  • Understanding of integral calculus
  • Familiarity with the Euler-Mascheroni constant
  • Knowledge of limits and convergence in integrals
  • Basic experience with mathematical transformations
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bbailey
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I am working on the integral representation of the Euler-Mascheroni constant and I can't seem to understand why the first of the two integrals is (1-exp(-u))lnu instead of just exp(-u)lnu. It is integrated over the interval from 1 to 0, as opposed to the second integral exp(-u)lnu which is integrated from 1 to infinity. I would appreciate any help on why the first integral is transformed from exp(-u)lnu to (1-exp(-u))lnu. thanks in advance
 
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