- #1

reaiy

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NVM I GET HOW TO DO I TNOW

"The region bounded by the graphs of [tex]y = \frac{x}{\sqrt{x^2+25}} [/tex], y = 0, and x = 5 is revolved about the

The only way i see to do this right now is to use shells, and the equation for that is

[tex] V = \int 2 \pi x f(x) [/tex] where the integral is from the lower limit to the upper limit

Mathematica can't find an answer to it. You can try it yourself if you want [Integral of 2*pi*x^2/(x^2+25)^(1/2)]Thanks in advance for your helpOh also, the correct answer is [tex] 25\pi[\sqrt{2}-\ln{\sqrt{2}+1}] \approx 41.85 [/tex]

EDIt: ok mathematica does get an answer, but is the a way to find it without a reduction formula for tanx^2*secx ?

## Homework Statement

"The region bounded by the graphs of [tex]y = \frac{x}{\sqrt{x^2+25}} [/tex], y = 0, and x = 5 is revolved about the

**y-axis**. Find the volume of the resulting solid."## Homework Equations

The only way i see to do this right now is to use shells, and the equation for that is

[tex] V = \int 2 \pi x f(x) [/tex] where the integral is from the lower limit to the upper limit

Mathematica can't find an answer to it. You can try it yourself if you want [Integral of 2*pi*x^2/(x^2+25)^(1/2)]Thanks in advance for your helpOh also, the correct answer is [tex] 25\pi[\sqrt{2}-\ln{\sqrt{2}+1}] \approx 41.85 [/tex]

EDIt: ok mathematica does get an answer, but is the a way to find it without a reduction formula for tanx^2*secx ?

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